我有一个对象，例如下面的示例
object = {
[0] {Name: "Foo", Customer: "Alex", Number: "33.2", Amt: 100.50, FileId: 12345611, FileNumber: "0987-123"}
[1] {Name: "Bar", Customer: "Josh" Number: "1", Amt: 100.50, FileId: 456546456, FileNumber: "0987-123"}
[2] {Name: "Foo", Customer: "Alex", Number: "33.2", Amt: 110.00, FileId: 12345611, FileNumber: "0987-123"}
[3] {Name: "Foo", Customer: "Frank", Number: "9.8", Amt: 100.50, FileId: 324234, FileNumber: "9999-123"}
[4] {Name: "Test2", Customer: "Bob" , Number: "1.9", Amt: 100.50, FileId: 782724, FileNumber: "0987-123"}
[5] {Name: "Foo", Customer: "Alex" , Number: "33.2", Amt: 50.80, FileId: 9872561, FileNumber: "8181-1273"}
}
我需要它看起来像下面的
groupedObject = {
[0] {Name: "Foo",
Rows: {
row: {
[0] {Number: "33.2", Customer: "Alex", Details: {
[0] {Amt: 210.50, Number: "33.2", FileId: 12345611, FileNumber: "0987-123"}
[0] {Amt: 50.80, Number: "33.2", FileId: 9872561, FileNumber: "8181-1273"}
}
}
[1] {Number: "9.8", Customer: "Frank", Details: {
[0] {Amt: 100.50, Number: "9.8", FileId: 324234, FileNumber: "9999-123"}
}
}
}
}
}
[1] {Name: "Bar",
Rows: {
row: {
[0] {Number: "33.2", Customer: "Josh", Details: {
[0] {Amt: 100.50, Number: "1", FileId: 456546456, FileNumber: "0987-123"}
}
}
}
}
}
[2] {Name: "Test2",
Rows: {
row: {
[0] {Number: "1.9", Customer: "Bob", Details: {
[0] {Amt: 100.50, Number: "1.9", FileId: 782724, FileNumber: "0987-123"}
}
}
}
}
}
}
我要完成的工作是按名称分组，然后按名称在名称中分组，然后在该客户中的客户详细信息以及具有相同fileID的详细信息需要合并行。 linq有可能吗？
如果需要可视化，下面是我需要的，但是使用XML。
<main>
<UniqueNames>
<randominfo>true</randominfo>
<randominfo2>false</randominfo2>
<head>
<Name>Foo</Name>
</head>
<rows>
<row>
<Number>"33.2"</Number>
<Customer>"Alex"</Customer>
<Details>
<Detail>
<Amt>210.50</Amt>
<Number>"33.2"</Number>
<FileId>12345611</FileId>
<FileNumber>"0987-123"</FileNumber>
</Detail>
<Detail>
<Amt>50.80</Amt>
<Number>"33.2"</Number>
<FileId>9872561</FileId>
<FileNumber>"8181-1273"</FileNumber>
</Detail>
</Details>
</row>
</rows>
</UniqueNames>
<UniqueNames>
<randominfo>true</randominfo>
<randominfo2>false</randominfo2>
<head>
<Name>Bar</Name>
</head>
<rows>
<row>
<Number>"33.2"</Number>
<Customer>"Josh"</Customer>
<Details>
<Detail>
<Amt>100.50</Amt>
<Number>"1"</Number>
<FileId>456546456</FileId>
<FileNumber>"0987-123"</FileNumber>
</Detail>
</Details>
</row>
</rows>
</UniqueNames>
<UniqueNames>
<randominfo>true</randominfo>
<randominfo2>false</randominfo2>
<head>
<Name>Test2</Name>
</head>
<rows>
<row>
<Number>"1.9"</Number>
<Customer>"Bob"</Customer>
<Details>
<Detail>
<Amt>100.50</Amt>
<Number>"1.9"</Number>
<FileId>782724</FileId>
<FileNumber>"0987-123"</FileNumber>
</Detail>
</Details>
</row>
</rows>
</UniqueNames>
</main>
我尝试了以下方法... 按名称对我的对象进行分组，然后为每个名称列出每个对象。
var testgroup = TestObject.GroupBy( item => item.Name)
.Select(group => new { Name = group.Key, Items = group.ToList() })
.ToList()
然后我还有另一个用于获取所有详细信息
var Details =
(from c in TestObject
group c by new
{
c.Number,
c.FileId,
c.FileNumber,
} into cFIDs
select new FileAllocation()
{
FileAmount = cFIDs.Sum(s => s.Amt),
Number = cFIDs.Key.Number,
FileId = cFIDs.Key.FileId,
FileNumber = cFIDs.Key.FileNumber,
}).ToList();
以上内容使我可以分组并生成所需的详细信息，并且第一个按名称分组并列出每个行的详细信息...我也尝试了以下操作。
我只是不确定如何将它们放在一起
答案 0 :(得分：1)
您需要3个独立的GroupBy语句，然后将每个语句投影到输出的正确属性。有几种方法可以实现，但可能最容易阅读的是这样的：
var result = inputs.GroupBy(x => x.Name)
.Select(g => new {
Name = g.Key,
Rows = g.GroupBy(x => new {x.Customer, x.Number})
.Select(g2 => new{
Number = g2.Key.Number,
Customer = g2.Key.Customer,
Details = g2.GroupBy(x => new {x.FileId,x.FileNumber})
.Select(g3 => new {Amt = g3.Sum(x => x.Amt), g2.Key.Number, g3.Key.FileId, g3.Key.FileNumber})
})
});
以下是一个实时工作示例，其中包含您的数据：https://dotnetfiddle.net/ozcWUM
以上使用匿名对象，您可以根据需要轻松地投影到自定义对象。例如，最后的投影显示为：
...
.Select(g3 => new FileAllocation{Amt = g3.Sum(x => x.Amt), g2.Key.Number, g3.Key.FileId, g3.Key.FileNumber})
...