我试图在我的React Native应用程序中的<Text>
标签中从api获取并显示特定数据。
我想做的是显示该api中第二个对象的名称。
这是我的代码:
class HomeSreen extends Component {
constructor(props) {
super(props);
this.state = {
dataSource: [],
};
}
componentDidMount() {
const request = new Request('http://jsonplaceholder.typicode.com/users');
fetch(request)
.then(response => response.json())
.then(responseJson => {
this.setState({
dataSource: responseJson,
});
});
}
render() {
return (
<View>
<Text>Home Screen</Text>
<Text>{this.state.dataSource[1].name}</Text>
</View>
);
}
}
和API:
[
{
"id": 1,
"name": "Leanne Graham",
"username": "Bret",
"email": "Sincere@april.biz",
"address": {
"street": "Kulas Light",
"suite": "Apt. 556",
"city": "Gwenborough",
"zipcode": "92998-3874",
"geo": {
"lat": "-37.3159",
"lng": "81.1496"
}
},
"phone": "1-770-736-8031 x56442",
"website": "hildegard.org",
"company": {
"name": "Romaguera-Crona",
"catchPhrase": "Multi-layered client-server neural-net",
"bs": "harness real-time e-markets"
}
},
{
"id": 2,
"name": "Ervin Howell",
"username": "Antonette",
"email": "Shanna@melissa.tv",
"address": {
"street": "Victor Plains",
"suite": "Suite 879",
"city": "Wisokyburgh",
"zipcode": "90566-7771",
"geo": {
"lat": "-43.9509",
"lng": "-34.4618"
}
},
"phone": "010-692-6593 x09125",
"website": "anastasia.net",
"company": {
"name": "Deckow-Crist",
"catchPhrase": "Proactive didactic contingency",
"bs": "synergize scalable supply-chains"
}
},
.
.
.
但是我无法获取所需的数据。 任何帮助将不胜感激
答案 0 :(得分:1)
这些数据是异步请求的,因此,在首次渲染时,API不会返回任何数据。
class HomeSreen extends Component {
constructor(props) {
super(props);
this.state = {
dataSource: [],
};
}
componentDidMount() {
const request = new Request('http://jsonplaceholder.typicode.com/users');
fetch(request)
.then(response => response.json())
.then(responseJson => {
this.setState({
dataSource: responseJson,
});
});
}
render() {
return (
<View>
<Text>Home Screen</Text>
{
this.state.dataSource.length === 0 ?
<Text>Waiting moment.</Text> :
<Text>{this.state.dataSource[1].name}</Text>
}
</View>
);
}
}
进行这些更改后,您可以可视化所需的数据。
答案 1 :(得分:0)
如果问题是请求完成后您的组件没有更新那个属性,那是因为您在dataSource
数组上进行了“浅合并”,因此React无法检测到更改数据。有几种处理方法:
fetch(request)
.then(response => response.json())
.then(responseJson => {
this.setState(prevState => {
return {
...prevState.dataSource,
dataSource: responseJson.map((obj, i)=>{ return {...dataSource[i], ...obj}},
}
});
});
https://reactjs.org/docs/optimizing-performance.html#shouldcomponentupdate-in-action
name
属性拉到组件状态的顶层class HomeSreen extends Component {
constructor(props) {
super(props);
this.state = {
dataSource: [],
screenTitle
};
}
componentDidMount() {
const request = new Request('http://jsonplaceholder.typicode.com/users');
fetch(request)
.then(response => response.json())
.then(responseJson => {
this.setState({
screenTitle: responseJson[1].name,
});
});
}
render() {
return (
<View>
<Text>Home Screen</Text>
<Text>{this.state.screenTitle}</Text>
</View>
);
}
}