Question

我编写的代码只是创建一个结构并将其打印成多行如何创建一个包含所有行的字符串

import pyperclip
symbol = input('Symbol = ')
width = int(input('Width = '))
height = int(input('Height = '))

while height > 0:
 print(symbol * width)
 height = height - 1

print('\nCopy to Clipboard ?\nY For Yes\nN For No\n')
sel = input('')
if sel == 'Y':
 pyperclip.copy('Here i want to copy the Structure')
elif sel == 'N':
 print('Done')

Answer 1

您可以使用f字符串和加法。

public IServiceProvider ConfigureServices(IServiceCollection services)
{
    //...

    // Some DIs in ConfigureService
    services.AddTransient<ICustomService, CustomService>(); //this should be passed later to handler
    services.AddHttpContextAccessor();

    //...

    // Adding authentication in ConfigureServices
    services.AddAuthentication("Basic")
        .AddScheme<CustomBasicAuthenticationOptions, CustomBasicAuthenticationHandler>("Basic", null);

    //...
}

这将产生与您的代码相同的输出，但是这次您具有唯一的字符串。

Answer 2

您可以使用列表推导来构建字符串，然后一次使用所有字符串

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
   <item >
       <rotate
           android:fromDegrees="45"
           android:toDegrees="-45"
           android:pivotX="15%"
           android:pivotY="-36%" >
           <shape
               android:shape="rectangle"  >
                   <padding
                       android:bottom="50dp"
                       android:left="0dp"
                       android:right="0dp"
                       android:top="0dp" />
               <gradient
                   android:angle="225"
                   android:endColor="@android:color/transparent"
                   android:centerColor="@android:color/transparent"
                   android:startColor="#999999"
                   android:centerY="0.1"
                   android:type="linear" />
           </shape>
       </rotate>
   </item>
</layer-list>

使用pyperclip将多行复制到python中的变量

2 个答案: