Question

如何获取完整年份的完整星期数，开始日期和结束日期。

注意

一周从星期日到星期六
第1周（例如：2020年1月1日至2020年1月4日）和上周的同一时间（例如：27年12月27日至2020年12月31日）

期望结果

WeekNo  WeekStartDate   WeekEndDate
===================================
   1    2019-01-01      2019-01-05
   2    2019-01-06      2019-01-12
   3    2019-01-13      2019-01-19
   4    2019-01-20      2019-01-26
   5    2019-01-27      2019-02-02
   6    2019-02-03      2019-02-09
   7    2019-02-10      2019-02-16
   8    2019-02-17      2019-02-23
   9    2019-02-24      2019-03-02
   ...
   ...upto end of the year

实际上我也rextester尝试过这个

Answer 1

如果您仅对 2019 感兴趣，那么以下代码将完全生成您想要的内容：

DECLARE @weekNum INT = 1;

WITH Weeks AS (
    SELECT @weekNum AS WeekNo
    UNION ALL
    SELECT WeekNo + 1 FROM Weeks WHERE WeekNo + 1 <= 53
)
SELECT  WeekNo,
        CASE
          WHEN WeekStartDate < '2019-01-01' THEN CONVERT(DATE, '2019-01-01')
          ELSE CONVERT(DATE, WeekStartDate)
        END AS WeekStartDate,
        CASE
          WHEN WeekEndDate > '2019-12-31' THEN CONVERT(DATE, '2019-12-31')
          ELSE CONVERT(DATE, WeekEndDate)
        END AS WeekEndDate
  FROM  (
        SELECT  WeekNo,
                DATEADD(WEEK, WeekNo - 1, '2018-12-30') AS WeekStartDate,
                DATEADD(WEEK, WeekNo - 1, '2019-01-05') AS WeekEndDate
          FROM  Weeks
        ) a

输出：

WeekNo  WeekStartDate   WeekEndDate
1       2019-01-01      2019-01-05
2       2019-01-06      2019-01-12
3       2019-01-13      2019-01-19
4       2019-01-20      2019-01-26
5       2019-01-27      2019-02-02
6       2019-02-03      2019-02-09
7       2019-02-10      2019-02-16
8       2019-02-17      2019-02-23
...
51      2019-12-15      2019-12-21
52      2019-12-22      2019-12-28
53      2019-12-29      2019-12-31

根据OP关于变量开始和结束日期的评论

在OP关于更改开始日期和结束日期的评论之后，我重新访问了代码，并使其可以在任意两个日期之间使用：

DECLARE @startDate DATE = CONVERT(DATE, '2019-01-01');
DECLARE @endDate DATE = CONVERT(DATE, '2019-12-31');
DECLARE @weekNum INT = 1;

WITH Weeks AS (
    SELECT @weekNum AS WeekNo
    UNION ALL
    SELECT WeekNo + 1 FROM Weeks WHERE WeekNo + 1 <= DATEDIFF(WEEK, @StartDate, @EndDate) + 1
)
SELECT  WeekNo,
        CASE
          WHEN WeekStartDate < @startDate THEN @startDate
          ELSE CONVERT(DATE, WeekStartDate)
        END AS WeekStartDate,
        CASE
          WHEN WeekEndDate > @endDate THEN @endDate
          ELSE CONVERT(DATE, WeekEndDate)
        END AS WeekEndDate
  FROM  (
        SELECT  WeekNo,
                DATEADD(WEEK, WeekNo - 1, OffsetStartDate) AS WeekStartDate,
                DATEADD(WEEK, WeekNo - 1, OffsetEndDate) AS WeekEndDate
          FROM  Weeks
            INNER JOIN  (
                        SELECT  CASE
                                    WHEN DATEPART(WEEKDAY, @startDate) = 1 THEN @startDate
                                    ELSE DATEADD(DAY, 1 - DATEPART(WEEKDAY, @startDate), @startDate)
                                END AS OffsetStartDate,
                                CASE
                                    WHEN DATEPART(WEEKDAY, @startDate) = 1 THEN DATEADD(DAY, 6, @startDate)
                                    ELSE DATEADD(DAY, 7 - DATEPART(WEEKDAY, @startDate), @startDate)
                                END AS OffsetEndDate
                        ) a ON 1 = 1
        ) a

只需修改@startDate和@endDate以反映所需的开始和结束日期。字符串的格式为YYYY-MM-DD。

这将在两个日期之间输出可变的星期数，从指定的日期开始和结束（根据需要创建部分星期）。希望按照要求。

Answer 2

对马丁的上述回答稍作更新。您可以根据自己的偏好传递@startDate和@endDate。

DECLARE @startDate DATETIME = '2019-01-01'
DECLARE @endDate DATETIME = '2021-01-01'
DECLARE @totalWeeks BIGINT= NULL

SELECT @totalWeeks =datediff(ww,@startdate,@enddate)

DECLARE @weekNum INT = 1;
WITH Weeks AS (
    SELECT @weekNum AS WeekNo
    UNION ALL
    SELECT WeekNo + 1 FROM Weeks WHERE WeekNo + 1 <= @totalWeeks
)

SELECT  WeekNo,
        CASE
          WHEN WeekStartDate < @startDate THEN CONVERT(DATE, '2019-01-01')
          ELSE CONVERT(DATE, WeekStartDate)
        END AS WeekStartDate,
        CASE
          WHEN WeekEndDate > @endDate THEN CONVERT(DATE, '2019-12-31')
          ELSE CONVERT(DATE, WeekEndDate)
        END AS WeekEndDate
  FROM  (
        SELECT  WeekNo,
                DATEADD(WEEK, WeekNo - 1, @startDate) AS WeekStartDate,
                DATEADD(WEEK, WeekNo - 1, @endDate) AS WeekEndDate
          FROM  Weeks
        ) a
    OPTION (MAXRECURSION 1000);

如何在SQL Server中获取Compelete年的星期数，开始日期和结束日期？

2 个答案: