Question

错误：尝试获取非对象的属性'gender_id'

控制器：

public function printreports(Request $request)
{
$id = $request->get('select2'); //eg. id=1
$teachers = DB::table('teachers')->find($id);
return view('teachers.report1',compact('teachers'));
}

查看：

@foreach($teachers as $teacher)
{{$teacher->gender_id}}
@endforeach

如果我用Eloquent通过替换以下查询来做到这一点，那还是可以的，但是我想如上所述通过数据库查询来做到这一点。

$teachers = Teacher::find($id);

Answer 1

您需要在何处使用它，之后您将可以进行收藏。

$teachers = DB::table('teachers')->where('id', $id)->get();

使用查找时，您只有一个物品

Answer 2

使用foreach时不需要使用find()。

 @if(sizeof($teachers))
 {{$teachers->gender_id}}
 {{$teachers->gender_id}}//whatever field you need to display
 {{$teachers->gender_id}}//whatever field you need to display

 @endif

如果您使用get()，

$teachers = DB::table('teachers')->where('id','=',$id)->get();

@if(sizeof($teachers))
@foreach($teachers as $teacher)
 {{$teacher->gender_id}}
 {{$teacher->gender_id}}//whatever field you need to display
 {{$teacher->gender_id}}//whatever field you need to display

@endforeach
@endif

Answer 3

$teachers = DB::table('teachers')->find($id);将返回单个模型或null，请尝试使用$teachers = DB::table('teachers')->get();

Answer 4

如果您想返回集合以查看，请使用get()这样的方法：-

public function printreports(Request $request)
{
$id = $request->get('select2'); 
$teachers = DB::table('teachers')->where('id', $id)->get();
return view('teachers.report1',compact('teachers'));
}

Laravel 6：尝试获取非对象的属性

4 个答案: