我正在尝试找到加入健身俱乐部我的人员列表的最新成员。我的思考过程是找到最高的年份,然后找到最高的月份,但是我在执行它时遇到了麻烦。
这里是俱乐部的成员:
club.join(new Membership("Ellen", 2, 2016, 115.00));
club.join(new Membership("Eric", 1, 2017, 75.00));
club.join(new Membership("Ben", 3, 2015, 35.50));
club.join(new Membership("Matt", 12, 2014, 42.00));
club.join(new Membership("Luke", 5, 2010, 145.00));
club.join(new Membership("Jon", 6, 2017, 65.00));
club.join(new Membership("Ryan", 7, 2016, 0.00));
club.join(new Membership("Alan", 8, 2015, 195.00));
club.join(new Membership("Jaden", 9, 2015, 15.00));
club.join(new Membership("Dan P", 10, 2011, 25.00));
club.join(new Membership("Jack", 2, 2013, 80.75));
club.join(new Membership("Mrs. R", 1, 2014, 125.00));
club.join(new Membership("Dan S", 1, 2015, 45.00));
club.join(new Membership("Caleb", 10, 2016, 0.00));
club.join(new Membership("Jacob", 5, 2017, 10.00));
club.join(new Membership("Anny", 7, 2016, 110.00));
club.join(new Membership("Wendy", 7, 2015, 85.00));
club.join(new Membership("Natalie", 8, 2014, 0.00));
club.join(new Membership("Paul", 9, 2016, 20.00));
club.join(new Membership("Zuck", 10, 2017, 55.00));
这是我找到最近方法的代码:
int tempMonth = 13;
int tempYear = 3000;
ArrayList<Membership> ppl = new ArrayList<Membership>();
Iterator<Membership> itr = members.iterator();
while(itr.hasNext())
{
Membership item = itr.next();
if(members.size() == 0)
{
return null;
}
else
{
if(tempYear > item.getYear())
{
if(tempMonth > item.getMonth())
{
ppl.add(item);
itr.remove();
}
}
}
}
return ppl;
答案 0 :(得分:1)
您可以使用@Component({
template: `
<div *ngIf="todos$ | async as todos">
<div *ngFor="let todo of todos">
{{todo.name}}
</div>
</div>
`
})
export class TodosComponent implements OnInit, OnDestroy {
todos$: Observable<Todo[]>;
constructor(private store: Store<State>) {}
ngOnInit() {
this.todos$ = this.store
.pipe(select(selectTodos));
}
ngOnDestroy(): void {
}
}
和自定义Collections.max
对Comparator
的列表进行排序
Membership
您也可以使用Collections.max(members, Comparator.comparing(Membership::getYear)
.thenComparing(Membership::getMonth));
stream