Question

我正在尝试在Angular 8项目中编写一个函数。我有一个对象数组，想要删除其中值为空的所有key：value对。互联网上有很多例子，但似乎没有一个适合我。

我所拥有的：

{
        "flightID": "FooID",
        "direction": "DownFoo",
        "msgType": "FooType",
        "elemNb": "",
        "msgID": "",
    },
    {
        "flightID": "FooID2",
        "direction": "UpFoo",
        "msgType": "FooType2",
        "elemNb": "",
        "msgID": "",
    },

我想要什么：

    {
        "flightID": "FooID",
        "direction": "DownFoo",
        "msgType": "FooType",
    },
    {
        "flightID": "FooID2",
        "direction": "UpFoo",
        "msgType": "FooType2",
    },

我的尝试

myList: any[]

 removeEmptyValues() {
    if (this.myList) {

      this.myList.forEach((value) => {

        Object.keys(value).forEach((key) => {
          delete key[''];

        })
      })
    }
    console.log(this.myList);
  }

我希望delete key['']将删除键，如果该值为空，但它没有做任何事情。如果值为空，如何删除密钥？

Answer 1

尝试删除value [key]而不是key ['']

if (value[key] === '') {
  delete value[key];
}

Answer 2

var list = [{
        "flightID": "FooID",
        "direction": "DownFoo",
        "msgType": "FooType",
        "elemNb": "",
        "msgID": "",
    },
    {
        "flightID": "FooID2",
        "direction": "UpFoo",
        "msgType": "FooType2",
        "elemNb": "",
        "msgID": "",
}];

let result = Array.from(list, o=> Object.fromEntries(Object.entries(o).filter((i) => i[1] != (null || ''))));

console.log(result);

var list = [{
        "flightID": "FooID",
        "direction": "DownFoo",
        "msgType": "FooType",
        "elemNb": "",
        "msgID": "",
    },
    {
        "flightID": "FooID2",
        "direction": "UpFoo",
        "msgType": "FooType2",
        "elemNb": "",
        "msgID": "",
}];

let result = Array.from(list, o=> Object.fromEntries(Object.entries(o).filter((i) => i[1] != (null || ''))));

console.log(result);

Answer 3

您必须从对象中删除密钥

myList: any[]

 removeEmptyValues() {
    if (this.myList) {

      this.myList.forEach((value) => {

        Object.keys(value).forEach((key) => {
          delete this.myList[key]

        })
      })
    }
    console.log(this.myList);
  }

Answer 4

您必须检查该值是否为空，然后删除键。他们下面的代码。

myList: any[]

removeEmptyValues() {
  if (this.myList) {

    this.myList.forEach((value) => {

      Object.keys(value).forEach((key) => {
        if(!value[key]) delete value[key];
      })
    })
  }
  console.log(this.myList);
}

如何在TypeScript中删除对象数组中具有空值的键？

4 个答案: