Question

我正在使用此驱动程序https://mongodb.github.io/mongo-java-driver/3.4/driver/getting-started/quick-start/

MongoCollection<Document> collection = database.getCollection("blogs");
String text = "hey";
List<String> searched = new ArrayList<String>();
// MongoCursor<Document> cursor = collection.find("posts").sort(ascendingorder).iterator()

博客集合具有1个变量的json

{
    "_id": "randomid"
    "posts": "hey my name is bob"
}, 

{
    "_id": "randomid"
    "posts": "a hey my name is bob"
},

如果要在此示例中找到搜索到的文本的“嘿”，我想按升序将每个json排序到一个列表中。所有帖子按升序包含“嘿”

例如，上面的列表将是

searched = [
    { 
        "_id": "randomid"
        "posts": "a hey my name is bob"
    },

    {
        "_id": "randomid"
        "posts": "hey my name is bob"
    }

]

Answer 1

您可以尝试这样查询：

db.blogs.find({"posts": /.*hey.*/}).sort( { posts: -1 } )

或

db.blogs.find({'posts': {'$regex': 'hey', '$options': 'i'}}).sort({ posts: -1 })

Answer 2

随机ID将是mongodb创建的时间戳。您可以使用它进行排序。

<div class="col-md-6 form-group">
<label for="reg_city" class="control-label">City <span style="color:blue;"><b>*</b></span></label>
<input  name="reg_city" type="text"  class="form-control" required id="js_reg_city" placeholder="">
</div>

mongodriver升序排列

2 个答案: