Question

我对Regex真的很糟糕，但我想删除所有这些。，;：''$'@！？/ *＆amp; ^ - +字符串

string x = "This is a test string, with lots of: punctuations; in it?!.";

我该怎么做？

Answer 1

首先，请read here获取有关正则表达式的信息。值得学习。

您可以使用：

Regex.Replace("This is a test string, with lots of: punctuations; in it?!.", @"[^\w\s]", "");

这意味着：

[   #Character block start.
^   #Not these characters (letters, numbers).
\w  #Word characters.
\s  #Space characters.
]   #Character block end.

最后它会读取“替换任何不是单词字符或空格字符的字符。”

Answer 2

此代码显示了完整的RegEx替换过程，并提供了仅在字符串中保留字母，数字和空格的示例Regex-用空字符串替换所有其他字符：

$uri = explode('/', $_SERVER["REQUEST_URI"]);
$page = $uri[count($uri) - 2];

if(!(in_array($page, array("/*list of allowed pages*/")) || isset($_COOKIE['id'])))
{
    header("Location: " . HTTP . "?forbidden" ); //HTTP is the main directory of my website
    exit();
}

我还将代码存储在这里以备将来使用： http://code.justingengo.com/post/Use%20a%20Regular%20Expression%20to%20Remove%20all%20Punctuation%20from%20a%20String

此致

S。贾斯汀·根戈

http://www.justingengo.com

使用Regex从字符串中删除标点符号

2 个答案: