List<Item> Item = (from it in _context.Item
join iv in _context.ItemVersions on it.Id equals iv.ItemId
join iot in _context.ItemOriginalTitles on iv.Id equals iot.ItemVersionId
where term.ToLower() == "all" || (it.Name.ToLower() == term.ToLower() || it.Name.ToLower().Contains(term.ToLower()) || iot.Value.Contains(term) ||
queryable.Any(x => iot.Value.Contains(x.SearchText)))
select new Item
{
Id = it.Id,
Name = it.Name,
TypeCodeId = it.TypeCodeId,
TypeCode = it.TypeCode,
OriginalLangId = it.OriginalLangId,
SubGenreCodeId = it.SubGenreCodeId,
ItemVersions = it.ItemVersions
}
).Include("ItemVersions.OriginalTitles").ToList();
如您所见,我正在尝试将OriginalTitles
添加到ItemVersions
实体,但是不能做到这一点(OriginalTitles
始终是null
)。
物品模型:
public class Item
{
[Key]
public int Id { get; set; }
public string Name { get; set; }
public int TypeCodeId { get; set; }
public TypeCodes TypeCode { get; set; }
public int? OriginalLangId { get; set; }
public int SubGenreCodeId { get; set; }
public List<ItemVersion> ItemVersions { get; set; }
}
和我的ItemVersions模型:
public class ItemVersion
{
[Key]
public int Id { get; set; }
public string Name { get; set; }
public List<ItemOriginalTitle> OriginalTitles { get; set; }
public List<ItemShortTitle> ShortTitles { get; set; }
public List<ItemSynopsis> ItemSynopsis { get; set; }
public List<ItemLongSynopsis> ItemLongSynopsis { get; set; }
public List<ItemLanguage> ItemLanguages { get; set; }
public List<VersionChannel> VersionChannels { get; set; }
public bool IsDefault { get; set; }
public Item Item { get; set; }
public int ItemId { get; set; }
}
寻找一种可以立即包含它的方法,如果可能的话,无需对其进行迭代。谢谢
答案 0 :(得分:1)
尝试(将Include
方法移至join
子句(已选择表的地方):
List<Item> Item = from it in _context.Item
join iv in _context.ItemVersions.Include("OriginalTitles") on it.Id equals iv.ItemId
join iot in _context.ItemOriginalTitles on iv.Id equals iot.ItemVersionId
where term.ToLower() == "all" || (it.Name.ToLower() == term.ToLower() || it.Name.ToLower().Contains(term.ToLower()) || iot.Value.Contains(term) ||
queryable.Any(x => iot.Value.Contains(x.SearchText)))
select new Item
{
Id = it.Id,
Name = it.Name,
TypeCodeId = it.TypeCodeId,
TypeCode = it.TypeCode,
OriginalLangId = it.OriginalLangId,
SubGenreCodeId = it.SubGenreCodeId,
ItemVersions = it.ItemVersions
};
答案 1 :(得分:0)
因为我初始化了一个新对象,所以包含内部实体也没关系。我的解决方案是返回db对象,并将包含对象移至该对象:
Item = (from it in _context.Item.Include("ItemVersions.OriginalTitles")
join iv in _context.ItemVersions on it.Id equals iv.ItemId
join iot in _context.ItemOriginalTitles on iv.Id equals iot.ItemVersionId
where term.ToLower() == "all" || (it.Name.ToLower() == term.ToLower() || it.Name.ToLower().Contains(term.ToLower()) || iot.Value.Contains(term) ||
queryable.Any(x => iot.Value.Contains(x.SearchText)))
select it
).ToList();