Question

尝试让Xerces-C根据模式文件验证XML文件，但没有运气。下面的构造函数接收XML文件和模式文件的位置，并设置相关的成员变量：

Config::Config(const std::string& schemaFile, const std::string& XMLFile)
    : m_schemaFile(schemaFile),
      m_XMLFile(XMLFile)
{

    {
        //initialize
        try
        {
            xercesc::XMLPlatformUtils::Initialize();
            xalanc::XPathEvaluator::initialize();
        }
        catch (xercesc::XMLException& e)
        {
            throw XercesInitialisationException();
        }
    }

    {
        //validate XML
        xercesc::XercesDOMParser m_domParser;
        if (NULL == m_domParser.loadGrammar(m_schemaFile.c_str(), xercesc::Grammar::SchemaGrammarType))
        {
            //schema file could not be loaded
            throw SchemaLoadException();
        }

        ParserErrorHandler errorHandler;
        m_domParser.setErrorHandler(&errorHandler);
        m_domParser.setDoNamespaces(true);
        m_domParser.setDoSchema(true);
        m_domParser.setValidationConstraintFatal(true);
        m_domParser.setValidationSchemaFullChecking(true);

        m_domParser.parse(m_XMLFile.c_str());

        if (NULL == m_domParser.getDocument() || NULL == m_domParser.getDocument()->getDocumentElement())
        {
            throw XMLLoadException();
        }

        if (0 == m_domParser.getErrorCount())
        {
            std::cout << "Number of schema validation errors: " << m_domParser.getErrorCount() << std::endl;
        }
        else
        {
            //m_validated unsuccessfully against the schema
            throw SchemaValidationException();
        }
    }

    {
        //set up XPath interpreter
        const xalanc::XalanDOMString m_xalanXMLFile(m_XMLFile.c_str());
        const xercesc::LocalFileInputSource m_xalanInputSource(m_xalanXMLFile.c_str());

        // Initialise XalanSourceTree subsystem...
        xalanc::XalanSourceTreeInit sourceTreeInit;
        m_liaison = std::auto_ptr<xalanc::XalanSourceTreeParserLiaison>(new xalanc::XalanSourceTreeParserLiaison(m_domSupport));
        m_domSupport.setParserLiaison(m_liaison.get());
        m_document = m_liaison->parseXMLStream(m_xalanInputSource);
        m_prefixResolver = std::auto_ptr<xalanc::XalanDocumentPrefixResolver>(new xalanc::XalanDocumentPrefixResolver(m_document));
        m_evaluator = std::auto_ptr<xalanc::XPathEvaluator>(new xalanc::XPathEvaluator);
    }
}

设置XML解析的构造函数区域如下所示。这就是我认为问题所在：

//validate XML
        xercesc::XercesDOMParser m_domParser;
        if (NULL == m_domParser.loadGrammar(m_schemaFile.c_str(), xercesc::Grammar::SchemaGrammarType))
        {
            //schema file could not be loaded
            throw SchemaLoadException();
        }

        ParserErrorHandler errorHandler;
        m_domParser.setErrorHandler(&errorHandler);
        m_domParser.setDoNamespaces(true);
        m_domParser.setDoSchema(true);
        m_domParser.setValidationConstraintFatal(true);
        m_domParser.setValidationSchemaFullChecking(true);

        m_domParser.parse(m_XMLFile.c_str());

        if (NULL == m_domParser.getDocument() || NULL == m_domParser.getDocument()->getDocumentElement())
        {
            throw XMLLoadException();
        }

        if (0 == m_domParser.getErrorCount())
        {
            std::cout << "Number of schema validation errors: " << m_domParser.getErrorCount() << std::endl;
        }
        else
        {
            //m_validated unsuccessfully against the schema
            throw SchemaValidationException();
        }

编译并运行代码时，一切正常，但不会针对架构对XML执行验证。这意味着即使XML不符合架构，也会解析XML。检查后，我也能够确定所有模式的errorCount值都保持为0。

Answer 1

您必须在xml根节点上引用架构，如下所示：

<rootNode xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:noNamespaceSchemaLocation="Schema.xsd">

Xerces-C XML模式验证不起作用

1 个答案: