Question

我正在尝试抓取游戏的结果，但是有一个游戏进行了第三轮比赛，而有一个游戏没有进行比赛，因此在没有第三轮比赛的游戏中会发生错误，并且不要刮任何东西。

IndexError: list index out of range

部分代码：

player1_game1 = response.css('tbody tr:nth-child(1) td span::text').re('\d')[0]
player2_game1 = response.css('tbody tr:nth-child(2) td span::text').re('\d')[0]
player1_game2 = response.css('tbody tr:nth-child(1) td span::text').re('\d')[1]
player2_game2 = response.css('tbody tr:nth-child(2) td span::text').re('\d')[1]
player1_game3 = response.css('tbody tr:nth-child(1) td span::text').re('\d')[2]
player2_game3 = response.css('tbody tr:nth-child(2) td span::text').re('\d')[2]


items['player1_game1'] = player1_game1
items['player2_game1'] = player2_game1
items['player1_game2'] = player1_game2
items['player2_game2'] = player2_game2
items['player1_game3'] = player1_game3
items['player2_game3'] = player2_game3

如果我没有第三局，我什么也不想回答，将其留空，但将其余部分刮掉

错误：

IndexError: list index out of range

如何解决此问题并产生正确的结果？

Answer 1

您可以使用try...except块：

player1_game1 = response.css('tbody tr:nth-child(1) td span::text').re('\d')[0]
player2_game1 = response.css('tbody tr:nth-child(2) td span::text').re('\d')[0]
player1_game2 = response.css('tbody tr:nth-child(1) td span::text').re('\d')[1]
player2_game2 = response.css('tbody tr:nth-child(2) td span::text').re('\d')[1]
try:
    player1_game3 = response.css('tbody tr:nth-child(1) td span::text').re('\d')[2]
    player2_game3 = response.css('tbody tr:nth-child(2) td span::text').re('\d')[2]
except:
    player1_game3 = ""
    player2_game3 = ""

Scrapy IndexError：列表索引超出范围

1 个答案: