Question

Select main.gr_number from 
(
Select st.GR_NUMBER from student st where upper(st.class_id)=upper('jtm.online137') and st.is_active_flg='Y'
and st.status='STUDYING'
and upper(st.class_days) like  '%'||TO_CHAR(to_date('31-OCT-2019'),'DY')||'%'
) main 
where (Select GR_NUMBER  from student_class_attend where upper(class_id)=upper('jtm.online137')
and attend_date ='31-OCT-2019') not in (main.GR_NUMBER);

它给我错误

单行子查询返回多行

Answer 1

在我看来像NOT EXISTS，即

SELECT main.gr_number
  FROM (SELECT st.GR_NUMBER
          FROM student st
         WHERE     UPPER (st.class_id) = UPPER ('jtm.online137')
               AND st.is_active_flg = 'Y'
               AND st.status = 'STUDYING'
               AND UPPER (st.class_days) LIKE
                         '%'
                      || TO_CHAR (TO_DATE ('31-OCT-2019', 'dd-mon-yyyy'),
                                  'DY')
                      || '%') main
 WHERE NOT EXISTS
          (SELECT GR_NUMBER
             FROM student_class_attend
            WHERE     UPPER (class_id) = UPPER ('jtm.online137')
                  AND attend_date = TO_DATE ('31-OCT-2019', 'dd-mon-yyyy')
                  AND gr_number = main.GR_NUMBER);

请注意，我通过应用缺少的格式掩码和TO_DATE函数来修改了“日期”值，因为您不应该将日期与字符串进行比较。更好的是：使用日期文字，例如日期'2019-10-31'。

Answer 2

您不能将WHERE与返回多行的子查询一起使用。
代替使用WHERE尝试使用左联接，并（对于NOT IN）检查左联接键中的空值：

Select main.gr_number 
from  (
    Select st.GR_NUMBER 
    from student st 
    where upper(st.class_id)=upper('jtm.online137') 
    and st.is_active_flg='Y'
    and st.status='STUDYING'
    and upper(st.class_days) like  '%'||TO_CHAR(to_date('31-OCT-2019'),'DY')||'%'
) main 
LEFT JOIN (
  Select GR_NUMBER  
  from student_class_attend 
  where upper(class_id)=upper('jtm.online137')
    and attend_date ='31-OCT-2019'
)  t ON  t.GR_NUMBER main.GR_NUMBER 
      AND t.GR_NUMBER is null;

如何使用oracle比较两个列表值？

2 个答案: