我正在编写一个PHP脚本,为我做一些事情,所以我不必在我的网站文档中反复输入所有代码。
以下是我的工作:
// MyFunc.php
<?php
function DoStuff()
{
$var = 'something';
return $var;
}
?>
// index.php
<html>
<head></head>
<body>
Hi, I am currently doing <?php include "MyFunc.php"; echo DoStuff(); ?>, pretty cool, right?
</body>
</html>
然而,似乎我的功能没有被调用。我做错了吗?
以下是我的完整资料
//splashgen.php
<?php
$refid = $_GET['ref'];
$output = 'Company';
function GetSponsor()
{
if($refid!='')
{
$dbhost = "localhost";
$dbuser = "myuser";
$dbpass = "mypass";
$dbname = "mydb";
$sqlselect = "SELECT * FROM egbusiness_members WHERE loginid='$refid';";
$con = mysql_connect($dbhost,$dbuser,$dbpass) or die('Unable to connect to Database Server!');
mysql_select_db($dbname) or die('Could Not Select Database!');
$refid = stripslashes($refid);
$refid = mysql_real_escape_string($refid);
$result = mysql_query($sqlselect);
while ($row = mysql_fetch_array($result))
{
$output = $row['name_f']." ".$row['name_l']." (".$refid.")";
}
mysql_close($con);
}
return $output;
}
?>
/////////
// index.php
...
<font style="font-size:19px" color="#0093C4" face="Calibri"><b>
This page was brought to you by: <?php $_GET['ref']; include "../splashgen.php"; echo GetSponsor(); ?>
</b></font></div>
...
答案 0 :(得分:3)
<body>
Hi, I am currently doing <?php include "MyFunc.php"; echo DoStuff(); ?>, pretty cool, right?
</body>
并确保您的php文件应以<?php
答案 1 :(得分:2)
您希望DoStuff()
(带括号)实际调用该函数。除此之外,您的代码还可以。
答案 2 :(得分:1)
缺少括号?
echo DoStuff();
答案 3 :(得分:1)
你忘了在函数调用中添加括号..更改
<body>
Hi, I am currently doing <?php include "MyFunc.php"; echo DoStuff; ?>,
pretty cool, right?
</body>
到
<body>
Hi, I am currently doing <?php include "MyFunc.php";
echo DoStuff(); ?>, pretty cool, right?
</body>
<强>更新强>
在您的“完整来源”中回复您的更新..
更改
function GetSponsor() {
到
function GetSponsor($refid) {
和HTML
更改
<font style="font-size:19px" color="#0093C4" face="Calibri"><b>
This page was brought to you by: <?php $_GET['ref'];
include "../splashgen.php"; echo GetSponsor(); ?>
</b></font>
类似
<font style="font-size:19px" color="#0093C4" face="Calibri"><b>
This page was brought to you by:
<?php
include "../splashgen.php";
$refid = $_GET['ref'];
echo GetSponsor($refid); ?>
</b></font>
我还建议你清理这个$ refid,这样你就不会进行sql注射......
答案 4 :(得分:1)
我认为这是因为我使用的是一个未在函数中声明的变量,显然函数需要一个参数,如下所示:
Function DoStuff($var)
{
if($var != '')
{
return 'I am currently '.$var;
}
}
...
echo DoStuff('posting on Stack Overflow');
答案 5 :(得分:0)