Question

我正在编写一个代码，该代码在计算重量和里程后为用户提供其包裹的总数。它在工作之前就可以使用，但是在我进行了较小的更改之后，任何重量超过2磅的东西都无法打印出来。为什么会这样？

#include <stdio.h>
#include <stdlib.h>

int main(){
    int weight;
    int miles;
    double mileCost;
    int segment;
    int remainder;

    printf("Charge by weight:(We don't tale packages over 10lbs\n");
    printf("\n 1-2 lbs: $1.50\n 3-6 lbs: $3.70\n 7-10 lbs: $5.25\n ");
    printf("Enter your package's weight:\n");
    scanf("%d", &weight);


    printf("Charge by mile: \n");
    printf("$1.50 for every 500 miles\n");
    printf("Enter the total miles for your package:\n");
    scanf("%d", &miles);

    if(miles == 0 && weight == 0 && weight < 10){
        printf("Invalid entry! Try Again.");
    }

    segment= miles / 500;
    remainder = miles % 500;    
    if(remainder > 0)
        remainder = 1;

    if(weight <= 2){
        mileCost = 1.50 * (segment + remainder);
        printf("The charge for your package is: %f\n", mileCost);
    }
    if(weight > 2 && weight >= 6){
        mileCost = 3.70 * (segment + remainder);
        printf("The charge for your package is: %f\n", mileCost);
    }
    if(weight > 6 && weight >= 10){
        mileCost = 5.25 * (segment + remainder);
        printf("The charge for your package is: %f\n", mileCost);
    }
    return 0;
}

Answer 1

您的上限写为大于或等于<=，而不是小于或等于if(weight > 2 && weight >= 6){ if(weight > 6 && weight >= 10){：

if(weight > 2 && weight <= 6){
if(weight > 6 && weight <= 10){

应该是

{{1}}

Answer 2

关于：

if(weight > 2 && weight >= 6){

1）应该以{{1}}开头，因此如果体重<= 2甚至都不会看

2）声明应为：

else

注意else if(weight > 2 && weight <= 6){

3）存在以下类似考虑因素：

<= 6

有人可以告诉我为什么数学不打印吗？

2 个答案: