我不确定如何确定从其他类继承的类不相等。
我尝试使用isinstance来做到这一点,但是我对这种方法并不精通。
class FarmAnimal:
def __init__(self, age):
self.age = age
def __str__(self):
return "{} ({})".format(self, self.age)
from src.farm_animal import FarmAnimal
class WingedAnimal(FarmAnimal):
def __init__(self, age):
FarmAnimal.__init__(self, age)
def make_sound(self):
return "flap, flap"
from src.winged_animal import WingedAnimal
class Chicken(WingedAnimal):
def __init__(self, age):
WingedAnimal.__init__(self, age)
def __eq__(self, other):
if self.age == other.age:
return True
else:
return False
def make_sound(self):
return WingedAnimal.make_sound(self) + " - cluck, cluck"
from src.chicken import Chicken
from src.winged_animal import WingedAnimal
class Duck(WingedAnimal):
def __init__(self, age):
WingedAnimal.__init__(self, age)
def make_sound(self):
return WingedAnimal.make_sound(self) + " - quack, quack"
def __eq__(self, other):
if not isinstance(other, Duck):
return NotImplemented
return self.age == other.age
if __name__ == "__main__":
print(Chicken(2.1) == Duck(2.1))
因此在main方法中,它说要打印(Chicken(2.1)== Duck(2.1))并打印True,但是由于它们是不同的类,我希望它返回False。任何帮助将不胜感激。
答案 0 :(得分:2)
您可以在__eq__
中定义FarmAnimal
方法,检查self
的类是否也与other
的类相同:
def __eq__(self, other):
if self.age == other.age and self.__class__ == other.__class__
return True
else:
return False
,您不必在子类中编写特定的__eq__
方法。