Question

我有以下字符串

ACTGACTGACTGACTGACTGACTGACTGAC

我想以10个字符的行显示此字符串，每行分成5个字符的组

所以我的第一行是：

ACTGA CTGAC

如何实现？

Answer 1

您可以使用textwrap模块将数据分成10个字符的块，然后格式化每一行：

import textwrap

s = 'ACTGACTGACTGACTGACTGACTGACTGAC'

out = '\n'.join(line[:5] + ' ' + line[5:] for line in textwrap.wrap(s, 10))

print(out)

输出：

ACTGA CTGAC
TGACT GACTG
ACTGA CTGAC

Answer 2

简单的方法是使用理解力，请参见示例：

>>> the_string="ACTGACTGACTGACTGACTGACTGACTGAC"
>>> size_s=5 
>>> var_buff = ''
>>> output=[the_string[var_buff-size_s:var_buff] for var_buff in range(size_s, len(the_string)+size_s,size_s)]
>>> print(output)
['ACTGA', 'CTGAC', 'TGACT', 'GACTG', 'ACTGA', 'CTGAC']

Answer 3

通过这种方法，您可以设置每行和每个块的字符数：

s = 'ACTGACTGACTGACTGACTGACTGACTGAC'
m = 5  # chunk size
n = 10 # line size
tmp = [(s[i:i+m], s[i+m:i+n]) for i in range(0, len(s), n)]

for chunk1, chunk2 in tmp:
    print(chunk1 + ' ' + chunk2)

输出：

ACTGA CTGAC
TGACT GACTG
ACTGA CTGAC

Answer 4

您可以编写自己的生成器函数：

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哪种产量（但也可以根据其他长度进行调整）

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Answer 5

类似的东西应该起作用。仅适用于五个字符的组

string='ACTGACTGACTGACTGACTGACTGACTGAC'

string = list(string)

while string:
    if len(string)>=10:
        print(''.join(string[:5])+' '+''.join(string[5:10])+'\n')
        string = string[10:]
    else:
        print(''.join(string[:5]))
        string = string[5:]

如何以10个字符的行显示字符串

5 个答案: