Question

我有一个当前的SQL查询，内容如下：

SELECT
    WEEK,
    SUM(CASE WHEN WEEK = '$week1' THEN 1 ELSE 0 END) AS week_1_total,
    SUM(CASE WHEN WEEK = '$week2' THEN 1 ELSE 0 END) AS week_2_total,
    SUM(CASE WHEN WEEK = '$week3' THEN 1 ELSE 0 END) AS week_3_total,
    SUM(CASE WHEN WEEK = '$week4' THEN 1 ELSE 0 END) AS week_4_total,
    SUM(CASE WHEN WEEK = '$week1' AND TYPE = 'refund' THEN 1 ELSE 0 END) AS week_1_refunds,
    SUM(CASE WHEN WEEK = '$week2' AND TYPE = 'refund' THEN 1 ELSE 0 END) AS week_2_refunds,
    SUM(CASE WHEN WEEK = '$week3' AND TYPE = 'refund' THEN 1 ELSE 0 END) AS week_3_refunds,
    SUM(CASE WHEN WEEK = '$week4' AND TYPE = 'refund' THEN 1 ELSE 0 END) AS week_4_refunds,
    SUM(CASE WHEN WEEK = '$week1' AND TYPE = 'closure' THEN 1 ELSE 0 END) AS week_1_closures,
    SUM(CASE WHEN WEEK = '$week2' AND TYPE = 'closure' THEN 1 ELSE 0 END) AS week_2_closures,
    SUM(CASE WHEN WEEK = '$week3' AND TYPE = 'closure' THEN 1 ELSE 0 END) AS week_3_closures,
    SUM(CASE WHEN WEEK = '$week4' AND TYPE = 'closure' THEN 1 ELSE 0 END) AS week_4_closures,
    SUM(CASE WHEN WEEK = '$week1' AND history LIKE '%rejected%' THEN 1 ELSE 0 END) AS week_1_rejections,
    SUM(CASE WHEN WEEK = '$week2' AND history LIKE '%rejected%' THEN 1 ELSE 0 END) AS week_2_rejections,
    SUM(CASE WHEN WEEK = '$week3' AND history LIKE '%rejected%' THEN 1 ELSE 0 END) AS week_3_rejections,
    SUM(CASE WHEN WEEK = '$week4' AND history LIKE '%rejected%' THEN 1 ELSE 0 END) AS week_4_rejections
FROM
    my_table
WHERE
    YEAR = '$SafeFY' AND period = '$SafePeriod'
GROUP BY
    WEEK

此查询有效，并向我获取了我想要的数据，但是由于我做的方式，这些数据已经遍历。

我只是这样做，因为这是我知道的唯一方法。我想像这样在PHP循环中使用结果：

echo '<table><opening tags> <etc...>'
while($Row = $Result->fetch_array(MYSQLI_ASSOC)) {
//HTML table rows with $Row['stuff'] here.
}
echo '</etc...></closing tags></table> '

但是数据是错误的打印表格的方式，如下所示：

| Week | Total  | Refunds | Closures | Rejections |
|  1   |   44   |    32   |   12     |     3      |
|  2   |   40   |    21   |   19     |     6      |
|  3   |   40   |    22   |   18     |     3      |
|  4   |   41   |    32   |   11     |     6      |

我不介意更改查询以在没有数据透视的情况下获得所有相同的结果，因此我可以像以前那样循环遍历它们，或者不使用PHP数组进行操作以使我可以遍历此查询结果，无论哪种更容易/更好。怎么样？

Answer 1

好吧，我又看了一遍，我想我只是在加倍努力。

继续以下假设： 1）数据库通常比PHP更擅长对数据进行排序/组织，因此更改查询可能比事后更改数组更好。 2）如果我希望结果有5列，则可能需要在语句中有5个选择

然后，我查看了GROUP BY部分，并意识到无论如何它已经将结果按周进行了拆分，因此我按总和进行了精简，然后GROUP BY部分将结果分成了几周，没有需要每周在选定部分中手动汇总。

SELECT
    WEEK,
    SUM(CASE WHEN YEAR = '2019' THEN 1 ELSE 0 END) AS total,
    SUM(CASE WHEN TYPE = 'refund' THEN 1 ELSE 0 END) AS refunds,
    SUM(CASE WHEN TYPE = 'closure' THEN 1 ELSE 0 END) AS closures,
    SUM(CASE WHEN history LIKE '%rejected%' THEN 1 ELSE 0 END) AS rejections

FROM
    my_table
WHERE
    YEAR = '$SafeFY' AND period = '$SafePeriod'
GROUP BY
    WEEK

获取我已转入HTML表格的报告数据

1 个答案: