如何找到列表中最常见的起始字母？

Question

我是编程新手，这个问题可能很乏味。 假设我有一个list=['stack',....,'overflow']和一个len(list)=n。我想在列表中找到最常见的起始字母。即“我”。我尝试使用.startswith()和.most_common([n])，但没有得到结果。什么是好的方法？

Answer 1

您可以使用collections.Counter：

Counter(x[0] for x in lst).most_common()[0]

其中lst是您的列表。 （请注意，我已将您的列表重命名为lst ）

示例：

from collections import Counter

lst = ['stack', 'in', 'over', 'for', 'overflow'] 

print(Counter(x[0] for x in lst).most_common()[0])
# ('o', 2)

Answer 2

您可以在下面使用实现。我已经解释了注释中的所有步骤。

words = ["a","b","a","d","d"] # it is your list

frequencies = [(letter, words.count(letter)) for letter in set(words)] #we are taking letters and their counts which is a tuple in a list
most_frequent_letter = sorted(frequencies, key=lambda x: x[1],reverse=True)[0] # and we are doing a stable sort for listing most frequent letters first.

print(most_frequent_letter)