Question

我写了一个短代码，输出斐波那契数列的前n个数字，其中n是传递的参数的值，每个数字都打印在新行中。我的问题是输出不是从0开始，而是从1开始。如何在输出中也获得0？

def fibonacci(n):
    fib1 = 0
    fib2 = 1
    for x in range(0,n):
        print("%d\n" %(fib2), end = " ")
        next = fib1 + fib2 
        fib1 = fib2
        fib2 = next

这是输出，为什么第一个输入后的数字为何？ output

Answer 1

def fibonacci(n):
    fib1 = 0
    fib2 = 1
    for x in range(0,n):
        print("%d\n" %(fib1), end = " ")
        next = fib1 + fib2 
        fib1 = fib2
        fib2 = next

简单打印fib1，而不是fib2的{{1}} 如果打印了line #5的{{1}}，那么在开始时如何期望输出0

Answer 2

您可以使用：

CREATE TABLE diagnosis (
    dia_ref number(12) not null,
    dia_type varchar2(20),
    dia_date date,
    dia_result varchar2(8), --Either Negative or positive.
    out_pat_ID number(5),
    in_pat_ID number(5),
    constraint chk_diagnosis_pat_id
        check ( (out_pat_id is not null and in_pat_id is null) or
                (out_pat_id is null and in_pat_id is not null)
              ),                 
    constraint dia_pk primary key (dia_ref),
    --one of the following is going to be null when you insert rows into this table since one diagnosis can only be associated with a single patient
    constraint dia_out_fk foreign key (out_pat_ID) references out_patient (out_pat_ID),
    constraints dia_in_fk foreign key (in_pat_ID) references in_patient (in_pat_ID)
);

或者，您可以只切换persons和def fibonacci(n): fib1 = 0 fib2 = 1 for x in range(0, n): print("%d" %(fib1)) fib1, fib2 = fib2, fib1 + fib2的值，而不必再弄乱代码了。

Answer 3

在其他示例中已提到，您可以解决您的问题..我正在分享更多的方法来实现..较短的代码

 def fibonacci_fun(n):
  a, b = 0, 1
  for x in range(2, n):
    print('%s' % a)
    a, b = b, a+b

 fibonacci_fun(n)

使用while循环的另一种方式

def fibonacci(n):
  a, b = 0, 1
  while a <= n:
    print(a)
    a, b = b, a+b

fibonacci(n)

fibonacci不输出0

3 个答案: