MVVM Firebase用户身份验证

时间:2019-11-02 22:24:51

标签: java android firebase mvvm firebase-authentication

由于我是MVVM和Firebase的新手,所以我尝试创建一个简单的应用程序来注册用户。 SignUp工作正常,但是随之而来的是一个奇怪的错误和应用程序崩溃。由于我也试图了解MVVM,因此,我希望获得一些技巧来完善代码。任何使它更好的帮助。谢谢

MainActivity

package com.example.testingapp;

import androidx.annotation.NonNull;
import androidx.appcompat.app.AppCompatActivity;
import androidx.lifecycle.ViewModelProviders;

import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;

public class MainActivity extends AppCompatActivity implements View.OnClickListener {

    MainViewmodel model;
    EditText editEmail;
    EditText editPassword;
    Button btnSignUp;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        editEmail = findViewById(R.id.editEmail);
        editPassword = findViewById(R.id.editPassword);
        btnSignUp = findViewById(R.id.btnSignUp);
        btnSignUp.setOnClickListener(this);
        model = ViewModelProviders.of(this).get(MainViewmodel.class);
    }

    @Override
    public void onClick(View view) {
        model.email = editEmail.getText().toString().trim();
        model.password = editPassword.getText().toString().trim();
        model.signUp();
    }
}

MainViewmodel

package com.example.testingapp;

import androidx.lifecycle.ViewModel;

public class MainViewmodel extends ViewModel {

    repo repository;
    String email;
    String password;

    public MainViewmodel(){
        if(repository == null){
            repository = new repo();
        }
    }

    public void signUp(){
        repository.firebaseSignUp(email, password);
    }
}

回购

package com.example.testingapp;

import android.util.Log;

import androidx.annotation.NonNull;

import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;

import java.util.concurrent.Executor;

import static android.content.ContentValues.TAG;

public class repo {

    FirebaseAuth mAuth = FirebaseAuth.getInstance();


    public void firebaseSignUp(String email, String password){
        Log.d(TAG, "firebaseSignUp: Success" + email + password);
        mAuth.createUserWithEmailAndPassword(email, password)
                .addOnCompleteListener((Executor) this, new OnCompleteListener<AuthResult>() {
                    @Override
                    public void onComplete(@NonNull Task<AuthResult> task) {

                    }
                });


    }

}

1 个答案:

答案 0 :(得分:0)

您可以删除(Executor) this,。对我来说就是工作。