Question

我有这个脚本：

    let data = [
        {day: 1, time: '08:00', note: 'madrid'},
        {day: 2, time: '08:00', note: 'barcelona'},
        {day: 3, time: '10:00', note: 'juventus'},
    ]
    let days = [7, 1, 2, 3, 4, 5, 6]
    let list = []

    days.forEach(element => {
        let item = data.find(x => x.day === element)

        if (item) {
            list.push(item)
        } else {
            list.push({ day: element, time: undefined })
        }
    });

如果脚本被执行，它将起作用。它将显示从第一天到第七天的时间表。但是，我的问题是数据变量是动态的。因此，一天可能有多个时间表，例如：

    let data = [
      {day: 1, time: '08:00', note: 'madrid'}, {day: 1, time: '09:00', note: 'chelsea'},
      {day: 2, time: '08:00', note: 'barcelona'}, {day: 2, time: '09:00', note: 'mu'},
      {day: 3, time: '10:00', note: 'juventus'}
    ]

也许我应该每天制作一个内部数组（以天为键），这样我可以保存具有多个时间表的数据日。

我该怎么做？

Answer 1

你能做这样的事吗？

let data = [
    {day: 1, time: '08:00', note: 'madrid'}, {day: 1, time: '09:00', note: 'chelsea'},
    {day: 2, time: '08:00', note: 'barcelona'}, {day: 2, time: '09:00', note: 'mu'},
    {day: 3, time: '10:00', note: 'juventus'}
]
let days = [7, 1, 2, 3, 4, 5, 6];
let list = [];

days.forEach(day => {
    list.push({day, schedule: [...data.filter(d => d.day === day)]
        .map(d => ({time: d.time, note: d.note}))
    })
});

console.log(list);

Answer 2

好的，假设您有这个：

let days = [7, 1, 2, 3, 4, 5, 6]

let data = [
    {day: 1, time: '08:00', note: 'madrid'},
    {day: 1, time: '09:00', note: 'chelsea'},
    {day: 2, time: '08:00', note: 'barcelona'},
    {day: 2, time: '09:00', note: 'mu'},
    {day: 3, time: '10:00', note: 'juventus'}
]

我首先将过滤data数组以使用您的键获取所有对象，然后将所有这些项目推送到list结果变量中。一种解决方法是：


days.forEach( d => {
    let daySchedule = data.filter(elem => {
        elem.day === d;
    });

    if (daySchedule.length > 0) {
        daySchedule.forEach( elem => list.push(elem) );
    }
    else {
        list.push({ day: d, time: undefined })
    }
});

如果数据大于1，如何将数据存储在数组中？

2 个答案: