我有一列25天的每小时时间戳记值。我想利用它们之间的时差。我过去曾经尝试过该代码,但它给了我负面的价值。我有这个新代码,但是它有两个值,但是如何调整它以遍历column的值?
def time_diff(start, end):
if isinstance(start, datetime_time): # convert to datetime
assert isinstance(end, datetime_time)
start, end = [datetime.combine(datetime.min, t) for t in [start, end]]
if start <= end: # e.g., 10:33:26-11:15:49
return end - start
else: # end < start e.g., 23:55:00-00:25:00
end += timedelta(1) # +day
assert end > start
return end - start
答案 0 :(得分:0)
使用:
s = dataFrame.groupby(['DeviceName'])['Time_ist_td'].diff()
dataFrame['Time_diff']=s.where(s>pd.Timedelta(0),-s).dt.total_seconds()) // 60
基本概念:
s=pd.Series([-1,1])
print(s)
0 -1
1 1
dtype: int64
s=s.where(s>0,-s)
print(s)
0 1
1 1
dtype: int64