Question

我对节点表达很陌生。并且一直在尝试使用mocha，chai编写测试代码。这是源代码的一部分。

googleService.js：

const axios = require('./axios');

exports.hitGoogle = async (requestUrl, payload) => {
  let response = {};
  await axios.post(`${requestUrl}`, payload)
    .then((resp) => {
      response = resp;
      console.log(response);
    })
    .catch((err) => {
      console.error(err);
    });
  return response;
};

readGoogle.js

const googleService = require('./googleService');

exports.execute = async (data) => {
  console.log(`data ${JSON.stringify(data)}`);
  console.log(`Name ${data.name}`);
  console.log(`Salary ${data.salary}`);
  console.log(`Age ${data.age}`);
  const payload = { name: data.name, salary: data.salary, age: data.age };

  await googleService.hitGoogle('http://dummy.restapiexample.com/api/v1/create', payload)
    .then((response) => {
      if (response.status === 200 || response.status === 201) {
        console.log(response.status);
        return true;
      }
      return false;
    })
    .catch((err) => {
      console.log(err);
    });
  return true;
};

这是我的单元测试文件：

const readGoogle = require('./readGoogle');

const jmsPayload = { age: '23', name: 'test', salary: '123' };

describe('Google ', () => {
  it('POST: Google.', async () => {
     readGoogle.execute(jmsPayload).then((result) => {
     results = result;
    console.log(`Final Result : ${results.toString()}`);
  });
});

执行此测试文件时，发布成功

hitGoogle url=http://dummy.restapiexample.com/api/v1/create
hitGoogle payload=[object Object]
{ status: 200,
  statusText: 'OK',

从测试类传递到readGoogle.js的输入值也将在其中读取，

data {"age":"23","name":"test","salary":"123"}
Name test
Salary 123
Age 23

**But I am getting Promise as output.** 

**SO I have rendered the promised value to a normal string and getting 'true' as final output.**

还

1）这是测试async-await模块的正确方法吗？

2）我们是否需要在此测试代码中添加其他内容，例如Settimeout 还是beforeEach或afterEachblock？

3）我们是否需要使用Sinon进行间谍活动或在“有效载荷”中添加存根在googleService.js中？

任何人都可以帮助或建议我正确的道路吗？

尝试以异步方式按如下顺序逐个执行测试用例，

const readGoogle = require('./readGoogle');

const jmsPayload = { age: '23', name: 'test', salary: '123' };

const common = require('./common');
const chaiHttp = common.chaiHttp;
common.chai.use(chaiHttp);

describe('Google ', () => {
  common.mocha.before((done) => {
    // Wait for the server to start up
    setTimeout(() => {
      done();
    }, 1000);
  });

  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
  });
  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
    setTimeout(() => {
    }, 1000);
  });
  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
  });
  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
  });
  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
  });
  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
  });
  it('POST: Google.', async () => {
    const result = readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${result.toString()}`);
  });
});

但是我得到了

错误：超时超过2000毫秒。对于异步测试和挂钩，请确保调用了“ done（）”；如果返回一个Promise，请确保它可以解决

预先感谢

Answer 1

您可以使用以下两种解决方案：

1）回调约定：

describe('Google ', () => {
    it('POST: Google.', (done) => {
        readGoogle.execute(jmsPayload).then((result) => {
            results = result;
            console.log(`Final Result : ${results.toString()}`);
            done();
        }).catch((e) => {
            done();
        });
    });
});

2）异步/等待约定

describe('Google ', () => {
  it('POST: Google.', async () => {
    const results = await readGoogle.execute(jmsPayload);
    console.log(`Final Result : ${results.toString()}`);
  });
});

使用Chai和Mocha异步等待Node.js单元测试代码

1 个答案: