Question

我试图在用户每次输入“是”时添加25，然后打印结果，但是在将它们相加时，它始终缺少第一个响应。因此，如果我为乳制品键入“是”，我只会得到75％的收益？对于较大的代码，这是一项正在进行的工作，但是基本上，如果您现在对乳制品键入“是”，则应该将它们加起来等于100。

尝试了许多不同的选项，却无处可寻

import java.util.Arrays;
import java.util.Scanner;

public class question4 {
        public static void main(String[] args) {
            Scanner userTypes = new Scanner(System.in); //new object for user input
            String[] respondents = {"Cormac", "Orla", "Paul", "Sarah"};
            String[] questions = {"Are you allergic to Dairy?", "Are you allergic to nuts?", "Are you gluten intolerent?"};
            String[] decisions = new String [4];
            int dairy= 0;
            int nuts= 0;
            int gluten=0;           
            for (int i=0; i<= respondents.length -1 ;i++) {
                System.out.println(respondents[i]);         
                for (int j=0; j<= questions.length -1; j++) {
                    System.out.println(questions[j]);
                    decisions[j]=userTypes.nextLine();    
                    }
                System.out.println(Arrays.toString(decisions));
            }
            System.out.println("Allergy Results");              
            for (int k=0; k <= respondents.length - 1; k++ ){                   
                if (decisions[k].equals("Yes")) {
                    dairy= dairy + 25;                      
                }    
            }    
            System.out.println("Dairy Allergy Results = " + dairy + "%");
        }    
}

Answer 1

这里的问题是，对于每个受访者，您都将他们的答案记录在decisions[j]中，其中j是问题编号；但是随后您通过在decisions[k]上进行迭代来计算“是”的响应数，其中k是响应者数。

decisions[i]表示某个受访者对问题i的回答，或者表示第i个受访者对问题1的回答。您需要重新考虑如何存储这些数据。

此外，由于正在为每个受访者的每个decisions[j]编写j，因此每次都会覆盖该数组，这意味着您最终只会存储最后一个受访者的结果。

二维数组可能是一个很好的解决方案，其中decisions[i][j]表示第i位受访者对问题j的回答。

Answer 2

首先，让我们格式化代码。为了存储3个三个不同问题的4个不同用户的决策，您需要像这样的数组（数据结构）。另外，看起来您仅对（现在）对乳品问题的决定感兴趣。因此，只需在计算中检查一下即可。我已经更新了代码并添加了注释。需要更新存储结果的部分以及如何计算乳制品的总量。

import java.util.Arrays;
import java.util.Scanner;

public class Question {
    public static void main(String[] args) {
        Scanner userTypes = new Scanner(System.in); //new object for user input
        String[] respondents = {"Cormac", "Orla", "Paul", "Sarah"};
        String[] questions = {"Are you allergic to Dairy?", "Are you allergic to nuts?", "Are you gluten intolerent?"};
        String[][] decisions = new String [4][3];//You have 4 respondents and You have 3 questions
        int dairy= 0;
        int nuts= 0;
        int gluten=0;
        for (int i=0; i<= respondents.length -1 ;i++) {
            System.out.println(respondents[i]);
            for (int j=0; j<= questions.length -1; j++) {
                System.out.println(questions[j]);
                decisions[i][j]=userTypes.nextLine();
                }
            System.out.println("Decisions :: "+Arrays.toString(decisions[i]));//Need to print the result per user
        }
        System.out.println("Allergy Results");//If you are only interested in dairy decision for the 4 user
        for (int k=0; k <= respondents.length - 1; k++ ){
            if (decisions[k][0].equals("Yes")) {//for all user check the first decision (as your first question is about dairy)
                dairy= dairy + 25;
            }
        }
        System.out.println("Dairy Allergy Results = " + dairy + "%");           
        userTypes.close();
    }
}

Answer 3

好吧，最后我真正的基本解决方案是以下方法，虽然不理想，但是我是一个初学者：）

public class question4 {
        static void allergyTest() { //method for the allergy test
            Scanner userTypes = new Scanner(System.in); //new object for user input
            String[] respondents = {"Cormac", "Orla", "Paul", "Sarah"};//string array that contains the name of the people being surveyed 
            String[] questions = {"Are you allergic to Dairy?", "Are you allergic to nuts?", "Are you gluten intolerent?"};// string array to store the questions
            String[] decisions = new String [3];//string array to store the responses to the questions
            int dairy= 0; //int to store dairy percentage
            int nuts= 0;// int to store nuts percentage
            int gluten=0; //int to store gluten percentage

            for (int i=0; i<= respondents.length -1 ;i++) { // for loop to go through each respondent
                System.out.println(respondents[i]); //print their name

                for (int j=0; j<= questions.length -1; j++) { //then a for loop to loop through the questions for each respondent 
                    System.out.println(questions[j]); //print the actual question
                    decisions[j]=userTypes.nextLine(); //take the users input

                    while(!decisions[j].equals("yes")&& !decisions[j].equals("no")) { //check if the users input is valid, as in yes or no
                        System.out.println("please type yes or no as your answer"); //if not tell them to type it correctly
                        decisions[j]=userTypes.nextLine(); //store the yes or no once correctly typed 
                    }

                }

                if (decisions[0].equals("yes")) { //add up the yes
                    dairy = dairy +25; //lazy way of getting a percentage because I know the amount of respondents & answers
                }
                if (decisions[1].equals("yes")) {
                    nuts = nuts +25;
                }
                if (decisions[2].equals("yes")) {
                    gluten = gluten +25;
                }

            }
            System.out.println("Allergy Results");// print the results below
            System.out.println("Percentage of people allergic to dairy= "+ dairy +"%");
            System.out.println("Percentage of people allergic to nuts= "+ nuts +"%");
            System.out.println("People who think they are allergic to gluten= "+ gluten +"%");


        }


        public static void main(String[] args) { //call the allergy test
            allergyTest();


        }
}

我试图在用户每次输入“是”时添加25，然后打印结果，但在将它们相加时始终会丢失第一个响应

3 个答案: