如何通过将每个列表中的一个元素组合在一起，将两个不同对象的列表组合成一个列表？

时间：2019-11-01 06:29:31

标签： c# list

嗨，我正在尝试将两个列表与不同的对象组合在一起。

[{"SaveValues":[{"id":1,"allposition":{"x":-0.015270888805389405,
"y":9.267399787902832},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":1}],

"NoteValues":[{"movenumber":1,"notemsg":"Added one"}]},
{"SaveValues":[{"id":1,"allposition":{"x":-0.015270888805389405,
"y":9.267399787902832},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":2},{"id":1,
"allposition":{"x":-0.02840942144393921,"y":6.721944808959961},
"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":2}],
"NoteValues":[{"movenumber":2,"notemsg":"Added two"}]},
{"SaveValues":[{"id":1,"allposition":{"x":-0.015270888805389405,
"y":9.267399787902832},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":3},{"id":1,
"allposition":{"x":-0.02840942144393921,"y":6.721944808959961},
"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},"allscale":{"x":1.0,"y":1.0},
"linepos0":{"x":0.0,"y":0.0,"z":0.0},"linepos1":{"x":0.0,"y":0.0,"z":0.0},
"movetype":3},{"id":1,"allposition":{"x":-0.10085266828536987,
"y":4.49822473526001},"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},
"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":3}],"NoteValues":
[{"movenumber":3,"notemsg":"Added three"}]},{"SaveValues":
[{"id":1,"allposition":{"x":-0.015270888805389405,"y":9.267399787902832}
,"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},

"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":4},{"id":1,
"allposition":{"x":-0.02840942144393921,"y":6.721944808959961},
"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},"allscale":{"x":1.0,"y":1.0},"linepos0":{"x":0.0,"y":0.0,"z":0.0},
"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":4},{"id":1,"allposition"
:{"x":-0.10085266828536987,"y":4.49822473526001},
"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},
"allscale":{"x":1.0,"y":1.0},
"linepos0":{"x":0.0,"y":0.0,"z":0.0},"linepos1":{"x":0.0,"y":0.0,"z":0.0},
"movetype":4},{"id":1,"allposition":{"x":0.17862117290496827,"y":1.5408382415771485},
"allrotation":{"x":0.0,"y":0.0,"z":0.0,"w":1.0},"allscale":{"x":1.0,"y":1.0},
"linepos0":{"x":0.0,"y":0.0,"z":0.0},"linepos1":{"x":0.0,"y":0.0,"z":0.0},"movetype":4}],
"NoteValues":[{"movenumber":4,"notemsg":"Added four"}]}]

下面给出的类。

[System.Serializable]
public class PlayerHandler 
{
public int id; 
public Vector2 allposition;
public Quaternion allrotation;
public Vector2 allscale;

public Vector3 linepos0;
public Vector3 linepos1;
public int movetype;


public PlayerHandler(int ids,Vector2 allpos,Quaternion allrot,Vector2 allscal,Vector3 Line0,Vector3 Line1,int Moves)

{
    this.id = ids;
    this.allposition = allpos;
    this.allrotation = allrot;
    this.allscale = allscal;
    this.linepos0 = Line0;
    this.linepos1 = Line1;
    this.movetype = Moves;
}



}

[System.Serializable]
public class PlayerMovement
{
public int movenumber;
public string notemsg;

public PlayerMovement(int Movenum,string Note)
{
    this.movenumber = Movenum;
    this.notemsg = Note;

}

}

现在我有两个带有相应值的列表。

List<PlayerHandler> SaveValuesDeserialize = new List<PlayerHandler>();
List<PlayerMovement> NoteValuesDeserialzeList = new List<PlayerMovement>();

我想将上述两个列表合并为第三个列表，其中NoteValuesDeserialzeList [0]中的第0个元素，SaveValuesDeserialize [0]中的第1个元素，NoteValuesDeserialzeList [1]中的第2个元素，SaveValuesDeserialize [1]中的第三个元素直到所有值都加起来。

出现各种疑问。新添加的列表List<?>AllcombinedList =new List<?>();的对象是什么。

还要加上新列表的计数（两个列表的总计数）？

2 个答案:

答案 0 :(得分：1)

因为PlayerHandler和PlayerMovement的唯一祖先是对象，所以您只能创建对象列表：

List<object> AllcombinedList = new List<object>();

int count = Math.Min(SaveValuesDeserialize.Count, NoteValuesDeserialzeList.Count);
// Or raise an exception if SaveValuesDeserialize.Count != NoteValuesDeserialzeList.Count
// Or ask the user what to do with the rest if it can happen
// Else use count = SaveValuesDeserialize.Count for example if always same
for ( int index = 0; index < count; index++ )
{
  AllcombinedList.Add(NoteValuesDeserialzeList[index]);
  AllcombinedList.Add(SaveValuesDeserialize[index]);
}

也许您可以使用元组列表来实现您的目标：

var AllcombinedList = new List<Tuple<PlayerHandler, PlayerMovement>>();

int count = Math.Min(SaveValuesDeserialize.Count, NoteValuesDeserialzeList.Count);
// Or raise an exception if SaveValuesDeserialize.Count != NoteValuesDeserialzeList.Count
// Or ask the user what to do with the rest if it can happen
// Else use count = SaveValuesDeserialize.Count for example if always same
for ( int index = 0; index < count; index++ )
{
  var item = new Tuple<PlayerMovement, PlayerHandler>(NoteValuesDeserialize[index],
                                                      SaveValuesDeserialzeList[index]);
  AllcombinedList.Add(item);
}

或匿名元组：

var AllcombinedList = new List<(PlayerHandler, PlayerMovement)>();

int count = Math.Min(SaveValuesDeserialize.Count, NoteValuesDeserialzeList.Count);
// Or raise an exception if SaveValuesDeserialize.Count != NoteValuesDeserialzeList.Count
// Or ask the user what to do with the rest if it can happen
// Else use count = SaveValuesDeserialize.Count for example if always same
for ( int index = 0; index < count; index++ )
{
  AllcombinedList.Add((NoteValuesDeserialize[index], SaveValuesDeserialzeList[index]));
}

或者您可以创建一个提供键入和命名的类：

var AllcombinedList = new List<PlayerItem>();

int count = Math.Min(SaveValuesDeserialize.Count, NoteValuesDeserialzeList.Count);
// Or raise an exception if SaveValuesDeserialize.Count != NoteValuesDeserialzeList.Count
// Or ask the user what to do with the rest if it can happen
// Else use count = SaveValuesDeserialize.Count for example if always same
for ( int index = 0; index < count; index++ )
  AllcombinedList.Add(new PlayerItem
  {
    Movement = NoteValuesDeserialzeList[index],
    Handler = SaveValuesDeserialize[index]
  });

public class PlayerItem
{
  public PlayerMovement Movement { get; set; }
  public PlayerHandler Handler { get; set; }
}

例如，如果要管理其他项目，可以执行以下操作：

int count = Math.Max(SaveValuesDeserialize.Count, NoteValuesDeserialzeList.Count);
for ( int index = 0; index < count; index++ )
{
  var movement = index < NoteValuesDeserialzeList.Count 
               ? NoteValuesDeserialzeList[index] 
               : null;
  var handler = index < SaveValuesDeserialize.Count 
              ? SaveValuesDeserialize[index] 
              : null;
  AllcombinedList.Add(new PlayerItem
  {
    Movement = movement,
    Handler = handler
  });
}

您必须决定自己要如何处理其他项（当一项计数大于另一项计数时）：不执行任何操作，将另一项添加为null或创建默认实例。

答案 1 :(得分：-1)

通用List<T>在其定义中仅接受一种类型T。因此，您不能在其中包含不同类型的元素，所有元素都必须是同一类型。

您可以使用class或struct来保存和公开这两种数据类型，然后在通用T定义中使用此类或结构作为类型List<T> 。或者，您可以使用tuples。

如果您觉得这种方法过于复杂，则可以将T和List<T>的祖先PlayerHandler用作PlayerMovement的类型Object 1}}。

相关问题
最新问题