鉴于本地时间fromLocalTime
和state
,我想创建一个标题为hourUTC
的列,该列仅返回小时(以UTC时间表示)
给定数据:
> dput(head(smart1,10))
structure(list(fromLocalTime = structure(c(1567086360, 1567604820,
1568037120, 1571344680, 1565797140, 1568641740, 1565983980, 1567100520,
1569963060, 1563888180), class = c("POSIXct", "POSIXt"), tzone = ""),
state = c("GA", "GA", "GA", "GA", "TX", "TX", "TX", "TX",
"TX", "FL")), class = c("tbl_df", "tbl", "data.frame"), row.names = c(NA,
-10L))
> data.frame(smart1)
fromLocalTime state
1 2019-08-29 09:46:00 GA
2 2019-09-04 09:47:00 GA
3 2019-09-09 09:52:00 GA
4 2019-10-17 16:38:00 GA
5 2019-08-14 11:39:00 TX
6 2019-09-16 09:49:00 TX
7 2019-08-16 15:33:00 TX
8 2019-08-29 13:42:00 TX
9 2019-10-01 16:51:00 TX
10 2019-07-23 09:23:00 FL
我想要这样的输出:
> data.frame(smart1)
fromLocalTime state hourUTC
1 2019-08-29 09:46:00 GA 13
2 2019-09-04 09:47:00 GA 13
3 2019-09-09 09:52:00 GA 13
4 2019-10-17 16:38:00 GA 20
5 2019-08-14 11:39:00 TX 16
6 2019-09-16 09:49:00 TX 14
7 2019-08-16 15:33:00 TX 20
8 2019-08-29 13:42:00 TX 18
9 2019-10-01 16:51:00 TX 21
10 2019-07-23 09:23:00 FL 13
在excel中,我使用此公式根据状态获取时区。我知道这并不全部,但就我的数据而言,就足够了: = if(ISNUMBER(SEARCH(A1,“ WA,OR,CA,NV”))),“太平洋”,if(ISNUMBER(SEARCH(A1,“ MT,ID,WY,UT,CO,AZ,NM”)) ,“ Mountain”,if(ISNUMBER(SEARCH(A1,“ ND,SD,NE,KS,OK,TX,MN,IA,MO,AR,LA,WI,IL,TN,MS,AL”)),“,”中央”,如果(ISNUMBER(SEARCH(A1,“ MI,IN,OH,PA,NY,VT,ME,NH,MA,RI,CT,KY,NJ,DE,MD,WV,VA,NC,SC, GA,FL,DC“)),” Eastern“,if(ISNUMBER(SEARCH(A1,” AK“))),”阿拉斯加“,if(ISNUMBER(SEARCH(A1,” HI“))),”夏威夷“,” “))))))
答案 0 :(得分:1)
使用提供的表格,如果您只是想进行近似(而不担心夏令时),则可以执行类似的操作
smart1 %>% mutate(
approxUTC = lubridate::hour(fromLocalTime) + case_when(
state %in% c("WA","OR","CA","NV")~8,
state %in% c("MT","ID","WY","UT","CO","AZ","NM")~7,
state %in% c("ND","SD","NE","KS","OK","TX","MN","IA","MO","AR","LA","WI","IL","TN","MS","AL")~6,
state %in% c("MI","IN","OH","PA","NY","VT","ME","NH","MA","RI","CT","KY","NJ","DE","MD","WV","VA","NC","SC","GA","FL","DC")~5,
state %in% c("AK")~9,
state %in% c("HI")~10,
TRUE ~ NA_real_))