Question

我正在尝试找到一种将数组添加到属性的方法。目前，我毫不费力地添加了非承包人。

var root = JObject.Parse(contractJson.ToString());

//get company name node
var companyNameMatches = root.Descendants()
    .OfType<JObject>()
    .Where(x => x["question"] != null && x["question"].ToString() == "Name of the company");
//add answer result to company name node
foreach (JObject jo in companyNameMatches)
{
    jo.Add("answer", new JObject(new JProperty("result", Request.Form["Companyname"].ToString())));
}

因此，此行...如何使“答案”成为数组：

jo.Add("answer", new JObject(new JProperty("result", Request.Form["Companyname"].ToString())));

寻找此输出：

"answer":[ 
    { 
       "result": "value"
    }
 ]

Answer 1

您需要将answer属性设置为数组，因此应使用JArray。更改此行：

jo.Add("answer", new JObject(new JProperty("result", Request.Form["Companyname"].ToString())));

收件人：

// Create the object to put in the array
var result = new JObject(new JProperty("result", Request.Form["Companyname"].ToString()));
// Create the array as the value for the answer property
jo.Add("answer", new JArray { result });

Answer 2

这是因为您使用的是JObject。

使用JArray对象。 JArray是JContainer，它是一个JToken，您可以将其添加到JObject中。

例如，用户的json：

string[] parameterNames = new string[] { "Test1", "Test2", "Test3" };

JArray jarrayObj = new JArray();

foreach (string parameterName in parameterNames)
{
    jarrayObj.Add(parameterName);
}

string bDay = "2011-05-06";
string email = "dude@test.com";

JObject UpdateTestProfile = new JObject(
                               new JProperty("_delete", jarrayObj),
                               new JProperty("birthday", bDay),
                               new JProperty("email", email));

Console.WriteLine(UpdateTestProfile.ToString());

将数组添加到属性

2 个答案: