Question

M代码可以工作，但是我希望它使用Ace Jack Queen和King而不是1，11,12,13，但是我不知道如何更改我的代码，所以它会做到。

# imports random
import itertools, random

# make a deck of cards
deck = list(itertools.product(range(1, 14), ['Spade', 'Heart', 
'Diamond', 'Club']))

# shuffles the deck
random.shuffle(deck)

# draw five cards
howmany = int(input('How many cards do you want to display? '))
print('You got:')
for i in range(howmany):
    print(deck[i][0], 'of', deck[i][1])

当前结果。

您要显示多少张卡？ 4 你得到了：钻石11 俱乐部7 6颗钻石钻石八颗

例如，我希望它为第一个输出

钻石杰克

Answer 1

这就是我要做的。注意，我主要更改了代码的最后一部分。这是为了提供元组解包get dictionary method和f-strings的用例：

# imports random
import itertools, random

# make a deck of cards
deck = list(itertools.product(range(1, 14), ['Spade', 'Heart', 
'Diamond', 'Club']))

# shuffles the deck
random.shuffle(deck)

# have a dict of named cards
cards = {11: "Jack", 12: "Queen", 13: "King", 1:"Ace"}

# draw five cards
howmany = int(input('How many cards do you want to display? '))
print('You got:')
for i in range(howmany):
    card, suit = deck[i] # unpack the tuple to have cleaner code
    print(f"{cards.get(card, card)} of {suit}") # use f-string together with get

Answer 2

import itertools, random

deck = list(itertools.product(['Ace']+ list(range(2,11)) + ['jack','Queen','King'] ,['Spade','Heart','Diamond','Club']))

random.shuffle(deck)

print("You got:")
for i in range(1):
   print(deck[i][0], "of", deck[i][1])

如何在python中随机播放一副纸牌

2 个答案: