我在IB中创建了一个TextView ...我想写两个“段落”,这似乎有用,除了第二个写覆盖第一个。
我该如何解决这个问题?
首先写:
resultText.text =[NSString stringWithFormat:@"Decode Data: %@, \n%@\n\n",symbol.data, symbol.typeName]; // display it...
第二次写:
resultText.text = [NSString stringWithFormat:@"\nDatabase: \n%@ \n%@ \n%@",
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 0)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)]];
答案 0 :(得分:0)
在我看来,你只是将文本分配两次,而不是附加。解决这个问题的简单方法是将第二次写入更改为:
resultText.text = [NSString stringWithFormat:@"%@\nDatabase: \n%@ \n%@ \n%@",
resultText.text,
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 0)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)]];
这将保留您之前的文字。
编辑:
resultText.text =[NSString stringWithFormat:@"Decode Data: %@, %@",symbol.data, symbol.typeName];
resultText.text = [NSString stringWithFormat:@"%@\nDatabase: %@, %@, %@",
resultText.text,
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 0)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)],
[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)]];