您好，亲爱的stackoverflow社区， 我正在研究一个从arduino模块接收信息并将其显示为图表的项目。 问题是我有5个元素（温度，湿度等），并且我拥有的代码一次只能接收一个数字（例如：2838752458），如示例中所示，该数字有10位数字来自arduino，我想将它们一分为二，因此每两个元素都需要一个元素。 您可能会问为什么我不设置处理程序，以便我可以在一个分开的时间接收每个两个数字，但是我已经尝试过了，这给了我封闭的应用程序错误，因为我一次只能收到一个数字的代码。 / p>
public class Analysies extends AppCompatActivity {
Handler h;
String tekrar = "";
String dama = "";
String qaza = "";
String faaliat = "";
String rotobat = "";
private OutputStream outStream = null;
private static final UUID MY_UUID = UUID.fromString("00001101-0000-1000-8000-00805F9B34FB");
private static String address = "00:21:13:00:02:5B";
final int RECIEVE_MESSAGE = 1; // Status for Handler
private BluetoothAdapter btAdapter = null;
private BluetoothSocket btSocket = null;
private StringBuilder sb = new StringBuilder();
private Analysies.ConnectedThread mConnectedThread;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_analysies);
gifImageView = (GifImageView) findViewById(R.id.gifBro);
txt1 = (GifImageView) findViewById(R.id.afterAutotxt);
Handler handler = new Handler();
handler.postDelayed(new Runnable() {
@Override
public void run() {
txt1.animate().alpha(1f).setDuration(2000);
}
}, 1000);
h = new Handler() {
public void handleMessage(android.os.Message msg) {
switch (msg.what) {
case RECIEVE_MESSAGE:
// if receive massage
byte[] readBuf = (byte[]) msg.obj;
String strIncom = new
String(readBuf, 0, msg.arg1);
// create string from bytes array
sb.append(strIncom);
// append string
int endOfLineIndex = sb.indexOf("\r\n");
// determine the end-of-line
if (endOfLineIndex > 0) {
// if end-of-line,
String sbprint = sb.substring(0, endOfLineIndex); // extract string
sb.delete(0, sb.length());
sbprint.getBytes().toString();
////////////////////////////// HERE IS WHERE I CAN RECEIVE INFORMATION FROM ARDUINO ///////////////////////////////
}
//Log.d(TAG, "...String:"+ sb.toString() + "Byte:" + msg.arg1 + "...");
// Toast.makeText(CommunicationAuto.this, "String:" + sb.toString() , Toast.LENGTH_LONG).show();
break;
}
}
;
};
btAdapter = BluetoothAdapter.getDefaultAdapter(); // get Bluetooth adapter
checkBTState();
}
private BluetoothSocket createBluetoothSocket(BluetoothDevice device) throws IOException {
if(Build.VERSION.SDK_INT >= 10){
try {
final Method m = device.getClass().getMethod("createInsecureRfcommSocketToServiceRecord", new Class[] { UUID.class });
return (BluetoothSocket) m.invoke(device, MY_UUID);
} catch (Exception e) {
// Toast.makeText(getApplicationContext(), "Could not Insecure", Toast.LENGTH_SHORT).show();
}
}
return device.createRfcommSocketToServiceRecord(MY_UUID);
}
@Override
public void onResume() {
super.onResume();
// Set up a pointer to the remote node using it's address.
BluetoothDevice device = btAdapter.getRemoteDevice(address);
// Two things are needed to make a connection:
// A MAC address, which we got above.
// A Service ID or UUID. In this case we are using the
// UUID for SPP.
try {
btSocket = createBluetoothSocket(device);
} catch (IOException e) {
// Toast.makeText(getApplicationContext(), "Socket failed", Toast.LENGTH_SHORT).show();
}
// Discovery is resource intensive. Make sure it isn't going on
// when you attempt to connect and pass your message.
btAdapter.cancelDiscovery();
// Establish the connection. This will block until it connects.
// Toast.makeText(getApplicationContext(), "Connecting", Toast.LENGTH_SHORT).show();
try {
btSocket.connect();
// Toast.makeText(getApplicationContext(), "Connecting ok!", Toast.LENGTH_SHORT).show();
} catch (IOException e) {
try {
btSocket.close();
} catch (IOException e2) {
// errorExit("Fatal Error", "In onResume() and unable to close socket during connection failure" + e2.getMessage() + ".");
}
}
// Create a data stream so we can talk to server.
mConnectedThread = new Analysies.ConnectedThread(btSocket);
mConnectedThread.start();
}
@Override
public void onPause() {
super.onPause();
try {
btSocket.close();
} catch (IOException e2) {
// errorExit("Fatal Error", "In onPause() and failed to close socket." + e2.getMessage() + ".");
}
}
private void checkBTState() {
// Check for Bluetooth support and then check to make sure it is turned on
// Emulator doesn't support Bluetooth and will return null
if(btAdapter==null) {
Toast.makeText(getApplicationContext(), " Bluetooth is not supported. ", Toast.LENGTH_SHORT).show();
} else {
if (btAdapter.isEnabled()) {
} else {
Intent enableBtIntent = new Intent(BluetoothAdapter.ACTION_REQUEST_ENABLE);
startActivityForResult(enableBtIntent, 1);
}
}
}
private void errorExit(String title, String message){
Toast.makeText(getBaseContext(), title + " - " + message, Toast.LENGTH_LONG).show();
finish();
}
private class ConnectedThread extends Thread {
private final InputStream mmInStream;
private final OutputStream mmOutStream;
public ConnectedThread(BluetoothSocket socket) {
InputStream tmpIn = null;
OutputStream tmpOut = null;
// Get the input and output streams, using temp objects because
// member streams are final
try {
tmpIn = socket.getInputStream();
tmpOut = socket.getOutputStream();
} catch (IOException e) { }
mmInStream = tmpIn;
mmOutStream = tmpOut;
}
public void run() {
byte[] buffer = new byte[256]; // buffer store for the stream
int bytes; // bytes returned from read()
// Keep listening to the InputStream until an exception occurs
while (true) {
try {
// Read from the InputStream
bytes = mmInStream.read(buffer); // Get number of bytes and message in "buffer"
h.obtainMessage(RECIEVE_MESSAGE, bytes, -1, buffer).sendToTarget(); // Send to message queue Handler
} catch (IOException e) {
break;
}
}
}
/* Call this from the main activity to send data to the remote device */
public void write(String message) {
byte[] msgBuffer = message.getBytes();
try {
mmOutStream.write(msgBuffer);
} catch (IOException e) {
}
}
}
}
问题：如何将10位数字二一二分开并将它们加到分开的整数中，以便可以将其传递给图表活动？请给我举一个“ 1234567890”这个数字的例子。
here是我到目前为止创建的图表的输出。
谢谢！
答案 0 :(得分：0)
首先，请确保您的数字位数（例如：1234567890）始终可被2整除。嗯，那么我为您准备了一点技巧。
首先，将digits转换为String并在步骤2中运行for-loop，然后仅在 i-th 和使用循环到数组中产生每个字符串的第（i + 1）个位置。最后，您只需将数组中的String解析为图表中的int值，就可以从数组列表中读取项目并将其发送到图表中。这是我使用 Kotlin 编写的示例代码（但如果需要，我可以将其转换为 Java 代码）。如果您遇到任何问题，请随时发表评论。
fun main() {
val digits = 1234567890
val arr = arrayListOf<String>()
for (i in 0 until digits.toString().length step 2) {
val sub = "${digits.toString()[i]}${digits.toString()[i+1]}"
arr.add(sub)
}
println(arr)
}
快乐编码！
答案 1 :(得分：0)
这似乎可以满足您的要求：
import java.util.regex.*;
public class HelloWorld{
public static void main(String []args){
String s = "1234567890";
String pattern = "(\\d\\d)";
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(s);
while (m.find()) {
System.out.println(m.group(0));
}
}
}
并输出：
12
34
56
78
90