等待实际上并不等待返回值

Question

我正在编写一个使用蓝牙模块的React-native应用程序。我的目标是使扫描/连接/发现功能异步，以便我可以等待它并相应地管理返回值。

这是我现在拥有的代码：

 async writeData(data) {
    this.store.dispatch({type: "START_LOADER"})

    await this.manager.isDeviceConnected(this.deviceId).then(res => {
      if (res) {
        const device = this.store.getState().store.device

        device.writeCharacteristicWithoutResponseForService(
          data.serviceId,
          data.charId,
          data.dataToWrite
        ).then(res => {
          this.store.dispatch({type: "SET_STATUS", payload: `${data.message}!\n`})
          this.store.dispatch({type: "STOP_LOADER"})
        }).catch(error => {
          this.store.dispatch({type: "SET_ERROR", payload: error.message})
          this.store.dispatch({type: "STOP_LOADER"})
        })

        return true
      } else {
        const timeout = setTimeout(() => {
          this.store.dispatch({type: "STOP_LOADER"})
          this.store.dispatch({type: "SET_ERROR", payload: 'Function timeout: device not found'})

          return
        }, 10000)

        this.manager.startDeviceScan(null, null, (error, device) => {
          if (error) {
            this.store.dispatch({type: "SET_ERROR", payload: error.message})
            return
          }

          if (device.id === this.deviceId) {
            clearTimeout(timeout)

            this.store.dispatch({type: "SET_STATUS", payload: "North Sense found, stopping device scan...\n"})
            this.store.dispatch({type: "SET_DEVICE", payload: device})

            this.manager.stopDeviceScan();

            device.connect().then((device) => {
              this.store.dispatch({type: "SET_STATUS", payload: "device is connected!\n"})
              return device.discoverAllServicesAndCharacteristics()
            }).then((device) => {
              device.writeCharacteristicWithoutResponseForService(
                data.serviceId,
                data.charId,
                data.dataToWrite
              ).then(res => {
                this.store.dispatch({type: "SET_STATUS", payload: `${data.message}!\n`})
                this.store.dispatch({type: "STOP_LOADER"})
              }).catch(error => {
                this.store.dispatch({type: "SET_ERROR", payload: error.message})
                this.store.dispatch({type: "STOP_LOADER"})
              })
            }).catch((error) => {
              this.store.dispatch({type: "SET_ERROR", payload: error.message})
              this.store.dispatch({type: "STOP_LOADER"})
            });
          }
        });
      }
    }).catch(error => {
      this.store.dispatch({type: "SET_ERROR", payload: error.message})
      return error
    })
  }

此代码被插入到类的上下文中，因此，我使用此函数的方式如下：

  const blApi = new blApi(deviceId)

  console.log('1')
  blApi.writeData({
    serviceId: Config.SERVICE_ID,
    charId: Config.ADD_PROGRAM_CHAR_ID,
    dataToWrite: btoa(`4;${this.state.bearing};${Config.SENSING_LOCATION_INDEX}`),
    message: "Person has been successfully added.",
  })
  console.log('2')

日志不等待函数返回，特别是在触发超时的情况下（如果蓝牙设备不在身边）并且超时在10秒后到期，我希望函数等待那10个继续下一行之前的秒数。

我该如何解决？