Question

如何将反跳应用于下面的（code from Yup's github）异步验证？

let asyncJimmySchema = string().test(
  'is-jimmy',
  '${path} is not Jimmy',
  async (value) => (await fetch('/is-jimmy/' + value)).responseText === 'true',
});

Answer 1

您可以使用lodash.debounce自行实现：

import { debounce } from "lodash";

// ...

const ASYNC_VALIDATION_TIMEOUT_IN_MS = 1000;

const validationFunction = async (value, resolve) => {
  try {
    const response = await fetch('/is-jimmy/' + value);
    resolve(response.responseText === 'true');
  } catch (error) {
    resolve(false);
  }
};

const validationDebounced = debounce(validationNameFunction, ASYNC_VALIDATION_TIMEOUT_IN_MS);

然后在验证方案中：

let asyncJimmySchema = string().test(
  'is-jimmy',
  '${path} is not Jimmy',
  value => new Promise(resolve => validationDebounced(value, resolve)),
});

Answer 2

我认为这应该有效。它正在从 just-debounce-it 复制解决方案，但立即返回 Promise，这正是 Yup 所期望的。

const asyncDebouncer = (fn, wait, callFirst) => {
  var timeout;
  return function() {
    return new Promise(async (resolve) => {
      if (!wait) {
        const result = await fn.apply(this, arguments);
        resolve(result);
      }

      var context = this;
      var args = arguments;
      var callNow = callFirst && !timeout;
      clearTimeout(timeout);
      timeout = setTimeout(async function() {
        timeout = null;
        if (!callNow) {
          const result = await fn.apply(context, args);
          resolve(result);
        }
      }, wait);

      if (callNow) {
        const result = await fn.apply(this, arguments);
        resolve(result);
      }
    });
  };
};

let asyncJimmySchema = string().test(
  'is-jimmy',
  '${path} is not Jimmy',
  asyncDebouncer((value) => (await fetch('/is-jimmy/' + value)).responseText === 'true', 400),
});

Yup / Formik异步验证与去抖动

2 个答案: