Question

在fetchAll命令之后，我返回了以下数组

Array ( [0] => Array ( [Name] => tbl_events [0] => tbl_events [Engine] => MyISAM 
[1] => MyISAM [Version] => 10 [2] => 10 [Row_format] => Dynamic [3] => Dynamic 
[Rows] => 9 [4] => 9 [Avg_row_length] => 214 [5] => 214 [Data_length] => 2148 
[6] => 2148 [Max_data_length] => 281474976710655 [7] => 281474976710655 
[Index_length] => 2048 [8] => 2048 [Data_free] => 216 [9] => 216
[Auto_increment] => 1420 [10] => 1420 [Create_time] => 2019-10-08 15:21:32 
[11] => 2019-10-08 15:21:32 [Update_time] => 2019-10-23 19:00:02 
[12] => 2019-10-23 19:00:02 [Check_time] => 
[13] => [Collation] => latin1_swedish_ci [14] => latin1_swedish_ci [Checksum] => 
[15] => [Create_options] => [16] => [Comment] => [17] => ) )

我正在尝试获取Auto_increment的值，并将其分配给变量$ newID

我正在使用的代码是

    $sqlNEWID = "SHOW TABLE STATUS LIKE 'tbl_events'";
    $stmt = $conn->prepare($sqlNEWID);
    $stmt->execute();
    $newID_data = $stmt->fetchAll();
    print_r($newID_data);
    $newID = $newID_data['Auto_increment'];

但是那什么都不返回，我猜是因为数组是数组中的一个数组还是一系列数组？

有人能启发我吗？

Answer 1

我通过替换获得了理想的结果

$newID_data = $stmt->fetchAll();

使用

 $newID_data = $stmt->fetch(PDO::FETCH_ASSOC);

问题解决了！

PDO在fetchAll之后返回单节点值

1 个答案: