Question

我的问题是，当我选择datefrom和date显示错误时。“键'性别'未找到

现在即使我使用的Q对象仍然和以前一样问题。

search_gender = request.POST["gender"]
age_from = request.POST["age_from"]
age_to = request.POST["age_to"]
date_from = request.POST["date_from"]
date_to = request.POST["date_to"]

if date_from:
    date_from = datetime.strptime(request.POST["date_from"],"%d %B %Y")

if date_to:
    date_to = datetime.strptime(request.POST["date_to"],"%d %B %Y")

patient = PatientInfo()

p_male = 0
p_female = 0
age1 = 0
age2 = 0
date1 = 0
date2 = 0

if search_gender == 'male' :
    p_male = 1
if search_gender == 'female' :
    p_female = 1

if age_from:
    age1 = 1
if age_to:
    age2 = 1
if date_from:
    date1 = 1
if date_to:
    date2 = 1

if date1 and date2:
    patient = PatientInfo.objects.filter(
            Q(dateedit__range = (date_from,date_to))
            )

当我选择date_from和date_to时，

仍显示错误???甚至我没有选择男性或女性，即使我使用if.POST.has_key（'gender'）仍然错误我是django的新手..请事先提前帮助... ...

Answer 1

当尝试对该字典中不存在的键进行字典查找时，会引发您报告的错误 - 几乎就是错误告诉您的错误。

由于我要继续发布的是您发布的代码，我的猜测是无论出于什么原因，“gender”实际上并不存在于request.POST字典中。你需要找出原因。

通常，在处理字典时，最佳做法是首先检查密钥是否存在，或使用dict.get方法提供后备：

# Check for dictionary key
if request.POST.has_key('gender'):
    gender = request.POST['gender']

# or Provide fallback
gender = request.POST.get('gender', 'male') # if gender isn't present, 'male' will be returned

Answer 2

为此，表格非常有用！

类似的东西：

forms.py

from django import forms

class MyForm(forms.Form):
    GENDERS = (
        ('m','Male'),
        ('f', 'Female')
    )
    gender    = forms.CharField(choices=GENDERS, required=False)
    age_from  = forms.IntegerField()
    age_to    = forms.IntegerField()
    date_from = request.POST["date_from"]
    date_to   = forms.DateTimeField()


    def clean_gender(self):
        gender = self.cleanded_data.get('gender', 'm')

        #do something with gender

        return gender#now it has always a value

views.py：

def myform(request):

if request.method == "POST":
    form = MyForm(request.POST)

    if form.is_valid():
        gender = form.cleaned_data.get('gender')

        #do something with data...


else:
    form = MyForm()

return render_to_response('template.html', {'form':from})

django q对象条件匹配

2 个答案: