Question

我需要将String转换为List<Map<String, String>>>才能通过JUnit测试。我有这个：

String userAttributes = "[{name=test, cp=458999, lastname=test2}]";

我想要在测试中（Mockito）使用此值更改对服务器的调用，如下所示：

Mockito.when(template.search(Mockito.anyString, new AttributesMapper()).thenReturn(attributes);

我需要List<Map<String, String>>>来做到这一点：

user.setUserName(attributes.get("name"));

Answer 1

尝试使用正则表达式或按特殊字符分隔。首先从开头和结尾删除括号。之后，您可以将其分为,和=以收集要映射的字符串。

String userAttributes = "[{name=test, cp=458999, lastname=test2}]";

List<String> strings = Arrays.asList(userAttributes
      .replace("[{","").replace("}]","")
      .split(", "));
Map<String, String> collect = strings.stream()
      .map(s -> s.split("="))
      .collect(Collectors.toMap(s -> s[0], s -> s[1]));

System.out.println(collect.get("name"));

使用Pattern

的其他方法

Map<String, String> collect = Pattern.compile(",")
        .splitAsStream(userAttributes
                .replace("[{","").replace("}]",""))
        .map(s -> s.split("="))
        .collect(Collectors.toMap(s -> s[0], s -> s[1]));

或者如果您确实要使用List<Map<String, String>>>。但是之后，您将无法执行此操作user.setUserName(attributes.get("name"));

List<Map<String, String>> maps = strings.stream()
      .map(s -> s.split("="))
      .map(s -> Map.of(s[0], s[1]))
      .collect(Collectors.toList());

System.out.println(maps);

Answer 2

    String userAttributes = "[{name=test, cp=458999, lastname=test2}]";
    StringTokenizer stringTokenizer = new StringTokenizer(userAttributes,",");
    List<Map<String,String>> list = new ArrayList<>();
    while(stringTokenizer.hasMoreElements()){
        StringTokenizer stringTokenizer2 = new StringTokenizer((String)stringTokenizer.nextElement(),"=");
        while(stringTokenizer2.hasMoreElements()){
            Map<String, String> map = new HashMap<>();
            map.put( ((String)stringTokenizer2.nextElement()),((String)stringTokenizer2.nextElement()) );
            list.add(map);
        }
    }

    System.err.println(list.toString());

将String转换为List <Map <String，String >>>以进行测试

2 个答案: