Question

我正在寻找一个包含源IP，目标IP，时间和数据包长度的列表。如果有任何行包含相同的源IP和目标IP，我需要删除重复的行并显示开始时间，停止时间和总包长度。

def combine_data(source, dest, time, length):
    CombinePacket = []
    CombinePacket = [(source[i], dest[i], time[i], length[i]) for i in range(len(source))]
    counter = 0
    line = []

    for i, j in zip(source, dest):
        if(source[counter] and dest[counter] == source[counter+1] and dest[counter+1]):
            print(CombinePacket[counter-1], CombinePacket[counter])
            counter+=1
    return 0 


(['172.217.2.161'], ['10.247.15.39'], '13:25:31.044180', '0') 

(['172.217.2.161'], ['10.247.15.39'], '13:25:31.044371', '46')

我希望将这些行合并起来，它应该像这样：

(['172.217.2.161'], ['10.247.15.39'], '13:25:31:044180', '13:25:31:044371', '46')

Answer 1

您没有向测试代码中添加一些数据，我也不知道这是否是您的问题，但是您错误地比较了

中的值

source[counter] and dest[counter] == source[counter+1] and dest[counter+1]

因为它意味着

(source[counter]) and (dest[counter] == source[counter+1]) and (dest[counter+1])

您必须分别比较每个元素

source[counter] == source[counter+1] and dest[counter] == dest[counter+1]

或者您可以比较元组或列表

(source[counter], dest[counter]) == (source[counter+1], dest[counter+1])

您可以使用zip(source, dest):代替zip(CombinePacket, CombinePacket[1:])，并且将同时拥有两个合并的行，可用于创建新行。而且您将获得所有数据作为列表，以便可以将列表与[source, dest]

进行比较

results = []

for x, y in zip(combine_packet, combine_packet[1:]):
    if (x[0:2] == y[0:2]):  # `[source, dest]`
        data = [x[0], x[1], x[2], y[2], y[3]]
        print(data)  # (['172.217.2.161'], ['10.247.15.39'], '13:25:31:044180', '13:25:31:044371', '46')
        results.append(data)

但是我不知道是否可以有三行具有相同的source, dest以及这三行的预期结果。

def combine_data(source, dest, time, length):

    combine_packet = list(zip(source, dest, time, length))

    results = []

    for x, y in zip(combine_packet, combine_packet[1:]):
        if (x[0:2] == y[0:2]):
            #print(x)  # (['172.217.2.161'], ['10.247.15.39'], '13:25:31.044180', '0') 
            #print(y)  # (['172.217.2.161'], ['10.247.15.39'], '13:25:31.044371', '46')
            data = [x[0], x[1], x[2], y[2], y[3]]
            print(data)  # (['172.217.2.161'], ['10.247.15.39'], '13:25:31:044180', '13:25:31:044371', '46')
            results.append(data)

    return results


source = [['172.217.2.161'], ['172.217.2.161'], ['0.0.0.0']]
dest   = [['10.247.15.39'], ['10.247.15.39'], ['10.247.15.39']]
time   = ['13:25:31.044180', '13:25:31.044371', '13:25:31.044371']
length = ['0', '46', '123']

combine_data(source, dest, time, length)

如何遍历列表并合并数据

1 个答案: