Question

需要将大于输入数字的所有数字相加。种子就是这样，以便可以复制输出。

示例：

[12,16,45,3,32]

输入值：30

输出：

77

import java.util.*;

    public class SumAbove {
        public static void main(String[] args) {
            Scanner scnr = new Scanner(System.in);
            int seed = scnr.nextInt();
            Random rand = new Random(seed);


            System.out.println("Enter a positive integer between 1-100 to search above:");
            int minVal = scnr.nextInt();

            int[] arr = new int[rand.nextInt(100)+1];
            for (int i=0; i<arr.length; i++) {
                arr[i] = rand.nextInt(100)+1;
            }
            System.out.println(Arrays.toString(arr));


             int sum = 0;
             for (int i=0; i<arr.length; i++) {
             if (arr[i]>minVal) {
                    sum += i;
                }
             }
            System.out.println(sum);
        }
    }

Answer 1

您不需要sum += i;（如前所述），而只需要一个循环（因为您知道第一个循环之前的最小值），而不是sum += arr[i];。喜欢，

int minVal = scnr.nextInt(), sum = 0;
int[] arr = new int[rand.nextInt(100) + 1];
for (int i = 0; i < arr.length; i++) {
    arr[i] = rand.nextInt(100) + 1;
    if (arr[i] > minVal) {
        sum += arr[i];
    }
}
System.out.println(Arrays.toString(arr));
System.out.println(sum);

Answer 2

将sum += i替换为sum += arr[i]。

变量i只是位置。 arr[i]是该位置的值。

Answer 3

public static void main(String[] args) {

    int nums[] = { 12, 16, 45, 3, 32 };
    int value;
    int sum = 0;

    System.out.println("Enter a positive integer between 1-100 to search above: ");
    Scanner sc = new Scanner(System.in);
    value = sc.nextInt();

    for (int i = 0; i < nums.length; i++) {
        if (nums[i] > value)
            sum = nums[i] + sum;
    }
    System.out.println(sum);
}

Answer 4

这是在Java 8+中使用流实现的方法。

      int nValues = 5;
      int minValue = 1;
      int maxValue = 30;
      Random r = new Random();
      for (int i = 0; i < 10; i++) {
         int[] values = r.ints(nValues, minValue, maxValue + 1).toArray();

         // min to sum is the threshold
         int minToSum = r.nextInt(7) + 10; // between 10 an 16 inclusive


         int sum = Arrays.stream(values).filter(m -> m > minToSum).sum();

         System.out.println("sum = " + sum + " for greater than " + minToSum
               + " : " + Arrays.toString(values));
      }

以下输出。

sum = 65 for values greater than 11 : [2, 10, 14, 23, 28]
sum = 92 for values greater than 10 : [13, 18, 15, 19, 27]
sum = 94 for values greater than 12 : [25, 6, 14, 25, 30]
sum = 54 for values greater than 10 : [14, 8, 14, 26, 5]
sum = 22 for values greater than 15 : [15, 8, 13, 22, 14]
sum = 28 for values greater than 13 : [3, 28, 9, 6, 5]
sum = 87 for values greater than 13 : [5, 18, 25, 21, 23]
sum = 31 for values greater than 13 : [16, 7, 12, 2, 15]
sum = 42 for values greater than 15 : [7, 22, 20, 10, 5]
sum = 40 for values greater than 12 : [2, 2, 13, 27, 9]

大于输入值的数组中的数字求和

4 个答案: