Question

我想在组合框中选择“键”后获取“值”。例如，在第一个组合框中，我选择“ b”，在第二个组合框中，我选择“ e”，我想将这两个选项的总和（“ 7”）作为结果。我不知道“ num1”和“ num2”应该放在什么位置，或者我需要以其他方式进行操作？

'''python

import tkinter as tk
from tkinter import ttk

def main():

zestawienie={
"a": "1",
"b": "2",
"c": "3"
}

zestawienie2={
"d": "4",
"e": "5",
"f": "6"
}


root = tk.Tk()
root.title('Energy')
root.geometry('500x200')


def add():
    blank.delete(0, tk.END)
    Ans = float(num1) + float(num2)
    blank.insert(0, Ans)

tk.Label(root, text="Rodzaj źródła ciepła",bd=3).grid(column=0,row=0)
number1 = tk.StringVar()
tk.Label(root, text="System przyhotowania ciepłej wody").grid(column=0,row=2)
number2= tk.StringVar()


combo1 = ttk.Combobox(root,values=list(zestawienie.keys()),justify="center",textvariable=number1)
combo1.bind('<<ComboboxSelected>>', lambda event: label_selected.config(text=zestawienie[number1.get()]))
combo1.grid(column=0,row=1)  
combo1.current(0)




combo2 = ttk.Combobox(root,values=list(zestawienie1.keys()),justify="center",textvariable=number2)
combo2.bind('<<ComboboxSelected>>', lambda event: label_selected1.config(text=zestawienie1[number2.get()]))
combo2.grid(column=0,row=3) 
combo2.current(0)

label_selected = tk.Label(root, text="Not Selected")
label_selected.grid(row=0, column=3)

label_selected1 = tk.Label(root, text="Not Selected")
label_selected1.grid(row=0, column=4)


#num1=
#num2=


blank = tk.Entry(root)
ttk.Label(root, text = "The Answer is:").grid(row=4)
blank.grid(row=4, column=1)
tk.Button(root, text='Add', command=add).grid(row=4, column=3)


root.mainloop()
if __name__ == '__main__':
main()

'''

Answer 1

我建议您首先更改dict中的值。使用int或float代替str，因为您将要对这些值进行计算。

zestawienie={"a": 1, "b": 2, "c": 3}

zestawienie2={"d": 4, "e": 5, "f": 6}

接下来，您的代码中出现了一些错误，例如使用了错误的变量名。我必须修复它才能使GUI工作。修复这些问题后，可以通过以下方法解决您提出的问题：

def add():
    blank.delete(0, tk.END)
    Ans = zestawienie.get(number1.get()) + zestawienie2.get(number2.get())
    blank.insert(0, Ans)

完整代码：

import tkinter as tk
from tkinter import ttk

def main():

    zestawienie = {"a": 1, "b": 2, "c": 3}
    zestawienie2 = {"d": 4, "e": 5, "f": 6}

    root = tk.Tk()
    root.title('Energy')
    root.geometry('500x200')

    def add():
        blank.delete(0, tk.END)
        Ans = zestawienie.get(number1.get()) + zestawienie2.get(number2.get())
        blank.insert(0, Ans)

    tk.Label(root, text="Rodzaj źródła ciepła",bd=3).grid(column=0,row=0)
    number1 = tk.StringVar()
    tk.Label(root, text="System przyhotowania ciepłej wody").grid(column=0,row=2)
    number2= tk.StringVar()

    combo1 = ttk.Combobox(root,values=list(zestawienie.keys()),justify="center",textvariable=number1)
    combo1.bind('<<ComboboxSelected>>', lambda event: label_selected.config(text=zestawienie[number1.get()]))
    combo1.grid(column=0,row=1)
    combo1.current(0)

    combo2 = ttk.Combobox(root,values=list(zestawienie2.keys()),justify="center",textvariable=number2)
    combo2.bind('<<ComboboxSelected>>', lambda event: label_selected1.config(text=zestawienie2[number2.get()]))
    combo2.grid(column=0,row=3)
    combo2.current(0)

    label_selected = tk.Label(root, text="Not Selected")
    label_selected.grid(row=0, column=3)

    label_selected1 = tk.Label(root, text="Not Selected")
    label_selected1.grid(row=0, column=4)

    blank = tk.Entry(root)
    ttk.Label(root, text = "The Answer is:").grid(row=4)
    blank.grid(row=4, column=1)
    tk.Button(root, text='Add', command=add).grid(row=4, column=3)

    root.mainloop()

if __name__ == '__main__':
    main()

组合框中的字典。如何从选定的选项中获得价值？

1 个答案: