我正在尝试从PowerShell开发一种表单,该表单可以在无限循环中控制和监视脚本(在我的情况下为vbs,但也可以是其他任何脚本)的执行。
我是PowerShell的新手,所以我对代码结构表示歉意。英语不是我的母语,所以我也对错误表示歉意。
我使用PowerShell是因为我希望我的表单在Windows通知任务栏中有一个图标和一个菜单。到目前为止,我唯一得到的就是图标,但是我还将获得菜单。这不是问题。
在单击按钮后,我需要我的表单以每3秒在INFINITE循环中启动一个VisualBasic脚本,直到再次按下按钮(或其他按钮)为止。但是我得到的是一个无限循环无休止,因为一旦按下按钮,表单就会冻结,因为它位于do while循环中。
有人知道我该如何解决我的问题?主要目的是每3秒启动相同的VBS,直到我希望它停止...
作为测试,我尝试通过PowerShell程序启动的VisualBasic脚本是一个简单的MsgBox,我将其称为“ hello.vbs”:
MsgBox "hello world"
为此,我创建了3个代码文件。它以调用PowerShell命令的名为“ program.vbs”的VisualBasic脚本开头:
Set WshShell = CreateObject("WScript.Shell")
WshShell.Run chr(34) & "C:\Users\XXX\Desktop\Program\program.bat" & Chr(34), 0
Set WshShell = Nothing
其次,执行名为“ program.bat”的蝙蝠,该蝙蝠调用PowerShell脚本:
powershell -executionpolicy bypass -file "C:\Users\XXX\Desktop\Program\program.ps1"
最后,名为“ program.ps1”的MAIN脚本使用控制和监视指令创建表单:
[System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
[System.Reflection.Assembly]::LoadWithPartialName("System.Drawing")
$functions = {
function Test()
{
do
{
Invoke-Expression "C:\Users\XXX\Desktop\Programita\hello.vbs"
Start-Sleep -Seconds 2
}while ($Label2.Text -ne 0)
}
}
Function Principal {
$ProgIcon1 = "C:\Users\XXX\Desktop\Program\icon1.ico"
$ProgIcon2 = "C:\Users\XXX\Desktop\Program\icon2.ico"
$Form = New-Object System.Windows.Forms.Form
$ContextMenuProg = New-Object System.Windows.Forms.ContextMenu
$Menu = New-Object System.Windows.Forms.MenuItem
$Icon1 = New-Object System.Drawing.Icon ($ProgIcon1)
$Icon2 = New-Object System.Drawing.Icon ($ProgIcon2)
$Label1 = New-Object System.Windows.Forms.Label
$Label2 = New-Object System.Windows.Forms.Label
$ComButt1 = New-Object System.Windows.Forms.Button
$ComButt2 = New-Object System.Windows.Forms.Button
$objNotifyIcon = New-Object System.Windows.Forms.NotifyIcon
$Form.Text = "Application stopped"
$Form.Controls.Add($Label1)
$Form.Controls.Add($Label2)
$Form.Controls.Add($ComButt1)
$Form.Controls.Add($ComButt2)
$Form.Width = 260
$Form.Height = 180
$Form.FormBorderStyle = "FixedSingle"
$Form.MaximizeBox = $False
$Form.StartPosition = "CenterScreen"
$Form.Icon = $Icon2
$Label1.Text = "My first form with icon inside task bar"
$Label1.Left = 30
$Label1.Top = 20
$Label1.AutoSize = $True
$ComButt1.Text = "Start application"
$ComButt1.Left = 12
$ComButt1.Top = 100
$ComButt1.Width = 102
$ComButt2.Text = "Close application"
$ComButt2.Left = 124
$ComButt2.Top = 100
$ComButt2.Width = 102
$ComButt2.Add_Click({
[System.Windows.Forms.DialogResult]::Cancel
})
$ComButt2.DialogResult = [System.Windows.Forms.DialogResult]::Cancel
$Label2.Text=0
$ComButt1.Add_Click(
{
if ($Label2.Text -eq 0)
{
$Form.Text = "Active application"
$ComButt1.Text = "Application paused"
$Label2.Text = 1
$objNotifyIcon.Icon = $ProgIcon1
$Form.Icon = $ProgIcon1
#####
Start-Job -InitializationScript $functions -ScriptBlock {Test} -Name MyJob
#####
}else {
$Form.Text = "Application stopped"
$ComButt1.Text = "Launch application"
$Label2.Text = 0
$objNotifyIcon.Icon = $ProgIcon2
$Form.Icon = $ProgIcon2
Remove-Job -Name MyJob -Force
}
}
)
$Label2.Left = 30
$Label2.Top = 50
$Label2.AutoSize = $True
$objNotifyIcon.Icon = $ProgIcon2
$objNotifyIcon.ContextMenu = $ContextMenuProg
$objNotifyIcon.Visible = $True
$Form.ShowDialog()
$objNotifyIcon.Visible = $False
}
Principal
答案 0 :(得分:3)
可能可以使用Start-Job
。因此,在作业运行时,您的gui不会冻结。您可以使用Stop-Job
/ Remove-Job
`停止/删除作业。
答案 1 :(得分:1)
尝试一下:
Class Surrounding_Class
Private Stop_Flag As Boolean = False
Private Sub Btn_Handler(ByVal Sender As Object, ByVal e As EventArgs)
Stop_Flag = Not Stop_Flag
DoAction()
End Sub
Private Sub DoAction()
Do
Loop While Stop_Flag = False
End Sub
End Class