Question

我是Django的初学者。

使用：带有Python 3.6.3的Django 2.2.6

这是扩展现有用户模型的问题。我已经读过这个https://docs.djangoproject.com/en/2.2/topics/auth/customizing/#extending-the-existing-user-model 我想做的就是

使用默认身份验证。
扩展用户模型。
查看/管理我在/ admin中扩展的模型

但是，我看不到/ admin中扩展的内容。我已完成以下操作：

user.models.py：

from django.db import models
from django.contrib.auth.models import User

class UserInfo(models.Model):
    user = models.OneToOneField(User, unique = True, verbose_name = '學號', on_delete = models.CASCADE)
    sNickName = models.CharField(max_length = 16, verbose_name = "暱稱")
    iArticleNumber = models.PositiveIntegerField(verbose_name = "文章數")  # from 0 to 2,147,483,647
    sShortIntroduction = models.TextField(verbose_name = "短自介")

创建一个与用户一对一的模型

user.admin.py：

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin
from django.contrib.auth.models import User

from user.models import UserInfo

class UserInfoInline(admin.StackedInline):
    model = UserInfo
    can_delete = False
    verbose_name_plural = 'UserInfo'

class UserAdmin(BaseUserAdmin):
    inline = [UserInfoInline, ]

admin.site.unregister(User)
admin.site.register(User, UserAdmin)

在用户中添加UserInfo

我的/ admin显示如下： This page is the same as I did not add changes in user.admin.py. cannot find 'UserInfo' here.

我希望当我单击特定用户时，例如图片中的“ 410431135”，我可以看到和管理“ UserInfo”，它是我为扩展auth.models.User

而创建的

注意：我已经通过shell在特定的user.userinfo中添加了一些数据

谢谢！第一次在这里问问题。

Answer 1

尝试在admin.py文件中进行这些更改

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class UserInfoInline(admin.StackedInline):
    model = UserInfo
    can_delete = False
    verbose_name_plural = 'UserInfo'

class UserAdmin(UserAdmin):
    inlines = (UserInfoInline,)
    list_display = ('username', 'first_name', 'last_name','UserInfo')

admin.site.unregister(User)
admin.site.register(User, UserAdmin)

Answer 2

内联

const resp = {
  data: {
    id: '1',
    displayName: 'A',
    children: [{
      id: '2',
      displayName: 'B',
      children: [{
        id: '3',
        displayName: 'C',
        children: [
          //More nested array here
        ]
      }]
    }]
  }
}

const newKeys = {
  displayName: "label"
};
const renamedObj = this.renameKeys(resp.data, newKeys);
console.log(renamedObj);

function renameKeys(obj, newKeys) {
  const keyValues = Object.keys(obj).map(key => {
    let newKey = null
    if (key === 'displayName') {
      newKey = newKeys.displayName
    } else {
      newKey = key
    }
    if (key === 'children') {
      obj[key] = obj[key].map(obj => renameKeys(obj, newKeys));    
    }
    return {
      [newKey]: obj[key]
    };
  });
  return Object.assign({}, ...keyValues);
}

Django admin：扩展现有的用户模型。没有显示在管理网站中

2 个答案: