这种方式有效:
import pandas
import pyodbc
import datetime as dt
server = 'myserver'
db = 'mydb'
myparams = ['2017-02-01','2017-02-28', None] # None substitutes NULL in sql
connection_string = pyodbc.connect('DRIVER={SQL Server};server='+server+';DATABASE='+ db+';Trusted_Connection=yes;')
df = pandas.read_sql_query('EXEC PythonTest_Align_RSrptAccountCurrentMunich @EffectiveDateFrom=?,@EffectiveDateTo=?,@ProducerLocationID=?', connection_string, params = myparams)
但是这种方法不起作用:
import datetime as dt
today = dt.date.today()
prev_monday = today - dt.timedelta(days=9)
prev_sunday = today - dt.timedelta(days=3)
myparams = [prev_monday,prev_sunday, None] # None substitutes NULL in sql
connection_string = pyodbc.connect('DRIVER={SQL Server};server='+server+';DATABASE='+ db+';Trusted_Connection=yes;')
df = pandas.read_sql_query('EXEC PythonTest_Align_RSrptAccountCurrentMunich @EffectiveDateFrom=?,@EffectiveDateTo=?,@ProducerLocationID=?', connection_string, params = myparams)
错误消息:
cur.execute(*args)
pandas.io.sql.DatabaseError: Execution failed on sql 'EXEC PythonTest_Align_RSrptAccountCurrentMunich @EffectiveDateFrom=?,@EffectiveDateTo=?,@ProducerLocationID=?': ('HYC00', '[HYC00] [Microsoft][ODBC SQL Server Driver]Optional feature not implemented (0) (SQLBindParameter)')
在python中有传递日期参数的特定方法吗?
答案 0 :(得分:1)
我的猜测是SQL无法处理熊猫的datetime值,
尝试使用strftime
import datetime as dt
today = dt.date.today()
prev_monday = (today - dt.timedelta(days=9)).strftime('%Y-%m-%d')
prev_sunday = (today - dt.timedelta(days=3)).strftime('%Y-%m-%d')
myparams = [prev_monday,prev_sunday, None]
print(myparams)
['2019-10-14', '2019-10-20', None]