Question

我有一个自动完成的googleapi，可以正确获取纬度，经度和地址。当我尝试将这些值传递给PHP时，我对Java的无知使我做错了事，因为php没有接收到任何数据。

JS

 <h1>Autocomplete form</h1>
 <input id="searchMapInput" class="mapControls" type="text" placeholder="- Type your location here -">
 <ul id="geoData">
 <li>Full Address: <span id="location-snap"></span></li>
 <li>Latitude: <span id="lat-span"></span></li>
 <li>Longitude: <span id="lon-span"></span></li>
 </ul>

 <script>
 function initMap() {
 var input = document.getElementById('searchMapInput');

 var autocomplete = new google.maps.places.Autocomplete(input);

autocomplete.addListener('place_changed', function() {
    var place = autocomplete.getPlace();
    document.getElementById('location-snap').innerHTML = place.formatted_address;
    document.getElementById('lat-span').innerHTML = place.geometry.location.lat();
    document.getElementById('lon-span').innerHTML = place.geometry.location.lng();

   function redirectToPosition(position) { 
   window.location='a.php?lat='+place.geometry.location.lat+'&long='+place.geometry.location.lng;
   }      
   });
   }
   </script>

   <script src="https://maps.googleapis.com/maps/api/js?key=[API_KEY_goes here]&libraries=places&callback=initMap" async defer>
   </script>

服务器端PHP是这个（注释后编辑）

<?php
$latitude = (isset($_GET['lat']))?$_GET['lat']:'';
$longitude = (isset($_GET['long']))?$_GET['long']:'';
echo "Latitude:".$latitude."</br>";
echo "Longitude:".$longitude;
?>

我得到了网址 --- / a.php？lat = function％20（）{return％20a}＆long = function％20（）{return％20b}

和以下回显：

纬度：函数（）{返回a}

经度：函数（）{return b}

Answer 1

您应检查$_GET['lat']和$_GET['long']

<?php
$latitude = (isset($_GET['lat']))?$_GET['lat']:'';
$longitude = (isset($_GET['long']))?$_GET['long']:'';
echo "Latitude:".$latitude."</br>";
echo "longitude:".$longitude;
?>

将数据从JS传递到PHP无法正常工作

1 个答案: