如何使用辅助函数创建存储过程以更新两个字段mySQL

时间：2019-10-23 10:47:21

标签： mysql sql stored-procedures stored-functions dml

所以我在mySQL上有一些表：

CREATE TABLE IF NOT EXISTS `salarygrade` (
  `GRADE` INT(11) NOT NULL,
  `HOURLYRATE` FLOAT NOT NULL,
  PRIMARY KEY (`GRADE`));

================================================ ========================== 

   CREATE TABLE IF NOT EXISTS `staffongrade` (
  `STAFFNO` INT(11) NOT NULL,
  `GRADE` INT(11) NOT NULL,
  `STARTDATE` DATE NULL DEFAULT NULL,
  `FINISHDATE` DATE NULL DEFAULT NULL,
  INDEX `STAFFONGRADE_FK` (`STAFFNO` ASC),
  INDEX `STAFFONGRADE2_FK` (`GRADE` ASC),
  PRIMARY KEY (`GRADE`, `STAFFNO`),
  CONSTRAINT `FK_STAFFONG_STAFFONGR_SALARYGR`
  FOREIGN KEY (`GRADE`)
  REFERENCES `salarygrade` (`GRADE`),
  CONSTRAINT `FK_STAFFONG_STAFFONGR_STAFF`
  FOREIGN KEY (`STAFFNO`)
  REFERENCES `staff` (`STAFFNO`));

================================================ ========================== 

CREATE TABLE IF NOT EXISTS `campaign` (
  `CAMPAIGN_NO` INT(11) NOT NULL,
  `TITLE` VARCHAR(30) NOT NULL,
  `CUSTOMER_ID` INT(11) NOT NULL,
  `THEME` VARCHAR(40) NULL DEFAULT NULL,
  `CAMPAIGNSTARTDATE` DATE NULL DEFAULT NULL,
  `CAMPAIGNFINISHDATE` DATE NULL DEFAULT NULL,
  `ESTIMATEDCOST` INT(11) NULL DEFAULT NULL,
  `ACTUALCOST` FLOAT NULL DEFAULT NULL,
  PRIMARY KEY (`CAMPAIGN_NO`),
  INDEX `OWNS_FK` (`CUSTOMER_ID` ASC),
  CONSTRAINT `FK_CAMPAIGN_OWNS_CUSTOMER`
    FOREIGN KEY (`CUSTOMER_ID`)
    REFERENCES `customer` (`CUSTOMER_ID`)
    ON DELETE RESTRICT
    ON UPDATE RESTRICT);

================================================ ========================== 

CREATE TABLE IF NOT EXISTS `workson` (
  `STAFFNO` INT(11) NOT NULL,
  `CAMPAIGN_NO` INT(11) NOT NULL,
  `WDATE` DATE NOT NULL,
  `HOUR` FLOAT NULL DEFAULT NULL,

  PRIMARY KEY (`STAFFNO`, `CAMPAIGN_NO`, `WDATE`),
  INDEX `WORKSON_FK` (`STAFFNO` ASC),
  INDEX `FK_WORKSON_WORKSON2_CAMPAIGN_idx` (`CAMPAIGN_NO` ASC),
  CONSTRAINT `FK_WORKSON_WORKSON2_CAMPAIGN`
    FOREIGN KEY (`CAMPAIGN_NO`)
    REFERENCES `campaign` (`CAMPAIGN_NO`)
    ON DELETE RESTRICT
    ON UPDATE RESTRICT,
  CONSTRAINT `FK_WORKSON_WORKSON_STAFF`
    FOREIGN KEY (`STAFFNO`)
    REFERENCES `staff` (`STAFFNO`));

我想创建一个名为sp_finish_campaign (in c_title varchar(30))的存储过程，该过程获取广告系列的标题并通过将CAMPAIGNFINISHDATE更新为当前日期并将ACTUALCOST更新为广告活动，是根据不同日期的不同员工投入的小时数和薪资等级计算出来的（薪水等级根据工作人员ID以及根据{的STARTDATE和FINISHDATE {1}}表。

要计算staffongrade，我创建了一个辅助函数：

ACTUALCOST

我根据给定的DELIMITER // CREATE FUNCTION rate_on_date(staff_id int, given_date date) RETURNS int DETERMINISTIC BEGIN DECLARE salaryGrade int; SET salaryGrade = (select grade from staffongrade where staffno = staff_id AND (given_date BETWEEN STARTDATE AND FINISHDATE)); RETURN salaryGrade; END // DELIMITER ; 和grade参数返回工资staff_id：

given_date

gradetable

对于此参数，我假设我必须从select rate_on_date(1, "2018-02-02") as Grade_On_Date;表中获取它，如下所示：

workson

我尝试使用select语句获取薪资：

workson

pay

要计算select hourlyrate as 'grade' from salarygrade where rate_on_date(1, "2018-02-02") = grade;，我想我必须通过将ACTUALCOST列乘以成绩成本来进行计算，并在{中使用HOUR和WDATE列{1}}表作为我的存储过程的参数，该表将通过输入广告系列标题来计算和更新广告系列的STAFFNO和workson。 但是我该怎么做呢？

我只是对如何创建此过程感到困惑，也对如何在存储过程中正确使用这些辅助函数感到困惑。 我觉得这个问题很长，但是我真的不知道该问什么或应该采取什么方向来解决这个问题。

1 个答案:

答案 0 :(得分：1)

您实际上不需要功能。在您的情况下，mysql可以执行多表更新（请参见https://dev.mysql.com/doc/refman/8.0/en/update.html）

update  campaign c
join 
(select c.campaign_no,
         sum(hour * hourlyrate) cost
from campaign c
join workson  w on w.campaign_no = c.campaign_no
join staffongrade s on s .staffno = w.staffno and w.wdate between s.startdate and s.finishdate
join salarygrade g on g.grade = s.grade
group by c.campaign_no
) s 
on s.campaign_no = c.campaign_no
set actualcost = s.cost
where c.campaign_no = 1
;

子查询在哪里需要

如果您简化数据，这应该很容易证明； 

drop table if exists salarygrade,campaign,workson,staffongrade;

CREATE TABLE  `salarygrade` 
(  GRADE INT NOT NULL,
  hOURLYRATE decimal(10,2) NOT NULL
);
insert into salarygrade values(1,10),(2,20);

cREATE TABLE IF NOT EXISTS `staffongrade` (
  `STAFFNO` INT(11) NOT NULL,
  `GRADE` INT(11) NOT NULL,
  `STARTDATE` DATE NULL DEFAULT NULL,
  `FINISHDATE` DATE NULL DEFAULT NULL
  );

insert into staffongrade values
(1,1,'2019-01-01','2019-06-30'),(1,2,'2019-06-01','2019-12-31'),(2,1,'2019-01-01','2019-01-31');

CREATE TABLE IF NOT EXISTS `campaign` (
  `CAMPAIGN_NO` INT(11) NOT NULL,
  `CAMPAIGNSTARTDATE` DATE NULL DEFAULT NULL,
  `CAMPAIGNFINISHDATE` DATE NULL DEFAULT NULL,
  `ESTIMATEDCOST` INT(11) NULL DEFAULT NULL,
  `ACTUALCOST` FLOAT NULL DEFAULT NULL
  );

insert into campaign values (1,'2019-01-01','2019-12-31',null,null);

CREATE TABLE IF NOT EXISTS `workson` (
  `STAFFNO` INT(11) NOT NULL,
  `CAMPAIGN_NO` INT(11) NOT NULL,
  `WDATE` DATE NOT NULL,
  `HOUR` FLOAT NULL DEFAULT NULL
  );

insert into workson values
(1,1,'2019-01-01',1),(1,1,'2019-12-01',1),(2,1,'2019-01-01',1);

select * from campaign;
+-------------+-------------------+--------------------+---------------+------------+
| CAMPAIGN_NO | CAMPAIGNSTARTDATE | CAMPAIGNFINISHDATE | ESTIMATEDCOST | ACTUALCOST |
+-------------+-------------------+--------------------+---------------+------------+
|           1 | 2019-01-01        | 2019-12-31         |          NULL |         40 |
+-------------+-------------------+--------------------+---------------+------------+
1 row in set (0.00 sec)

要破折号，所以我会让你把更新放到一个过程中。

如果staffongrade的finishdate值为NULL，则需要清除一些数据。为简单起见，我将创建一个临时表来填补空白，并更改update语句以使用projectfinishdate（如果不知道，则替换一个合适的将来日期）。此代码将在更新之前插入您的过程中

如此

insert into staffongrade values
(1,1,'2019-01-01',null),(1,2,'2019-07-01',null),(2,1,'2019-01-01',null);

drop temporary table if exists staffongradetemp;
create temporary table staffongradetemp like staffongrade;

insert into staffongradetemp 
select s.STAFFNO,s.GRADE,s.STARTDATE,
         case when s.FINISHDATE is not null then s.finishdate 
         else date_sub((select s1.startdate 
            from staffongrade s1 
             where s1.STAFFNO = s.STAFFNO and s1.startdate > s.STARTDATE 
             order by startdate limit 1), interval 1 day)
         end
from staffongrade s
;

select * from staffongradetemp;

+---------+-------+------------+------------+
| STAFFNO | GRADE | STARTDATE  | FINISHDATE |
+---------+-------+------------+------------+
|       1 |     1 | 2019-01-01 | 2019-06-30 |
|       1 |     2 | 2019-07-01 | NULL       |
|       2 |     1 | 2019-01-01 | NULL       |
+---------+-------+------------+------------+
3 rows in set (0.00 sec)

所有最后的finshdates都保留为空，我们可以使用合并将其保留在更新语句中

update  campaign c
join 
(select c.campaign_no,
         sum(hour * hourlyrate) cost
from campaign c
join workson  w on w.campaign_no = c.campaign_no
join **staffongradetemp s** on s .staffno = w.staffno and w.wdate between s.startdate and **coalesce(s.finishdate,c.CAMPAIGNFINISHDATE)**
join salarygrade g on g.grade = s.grade
where c.campaign_no = 1
group by c.campaign_no
) s 
on s.campaign_no = c.campaign_no
set actualcost = s.cost
where 1 = 1;
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