我无法使用下面的python代码从spark_2.4.4结构化流连接到kafka_2.12-2.3.0。我的Scala版本是2.11.12，OpenJDK是1.8.0_222
from pyspark.sql import SparkSession
spark = SparkSession\
.builder\
.appName("kafka-spark-structured-stream")\
.getOrCreate()
dsraw = spark\
.readStream\
.format("kafka")\
.option("kafka.bootstrap.servers", "**kafka-broker-ID**:9092")\
.option("subscribe", "test")\
.option("startingOffsets", "earliest")\
.load()
以下是我通过更改版本（例如从2.11更改为2.12）多次尝试的spark-submit，但仍然失败：
$spark-submit --jars /opt/hadoop/spark/jars/spark-sql-kafka-0-10_2.11-2.4.4.jar,/opt/hadoop/spark/jars/kafka-clients-0.10.1.0.jar --master yarn --deploy-mode client /opt/hadoop/spark/spark-application/main/kafka-spark-structured-stream.py
$spark-submit --packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.4.4 --master yarn --deploy-mode client /opt/hadoop/spark/spark-application/main/kafka-spark-structured-stream.py
无论我如何通过spark-submit尝试不同的方式，我都会不断得到以下错误：
2019-10-23 15:40:37,096 INFO handler.ContextHandler: Started o.s.j.s.ServletContextHandler@cf7aac8{/SQL/execution,null,AVAILABLE,@Spark}
2019-10-23 15:40:37,096 INFO ui.JettyUtils: Adding filter org.apache.hadoop.yarn.server.webproxy.amfilter.AmIpFilter to /SQL/execution/json.
2019-10-23 15:40:37,097 INFO handler.ContextHandler: Started o.s.j.s.ServletContextHandler@5c593907{/SQL/execution/json,null,AVAILABLE,@Spark}
2019-10-23 15:40:37,118 INFO ui.JettyUtils: Adding filter org.apache.hadoop.yarn.server.webproxy.amfilter.AmIpFilter to /static/sql.
2019-10-23 15:40:37,120 INFO handler.ContextHandler: Started o.s.j.s.ServletContextHandler@38634422{/static/sql,null,AVAILABLE,@Spark}
2019-10-23 15:40:40,573 INFO state.StateStoreCoordinatorRef: Registered StateStoreCoordinator endpoint
check_1======check_1======check_1======check_1======check_1======check_1======check_1======check_1======check_1======check_1======
Traceback (most recent call last):
File "/opt/hadoop/spark/spark-application/main/test.py", line 15, in <module>
.option("startingOffsets", "earliest").load()
File "/opt/hadoop/spark/python/lib/pyspark.zip/pyspark/sql/readwriter.py", line 172, in load
File "/opt/hadoop/spark/python/lib/py4j-0.10.7-src.zip/py4j/java_gateway.py", line 1257, in __call__
File "/opt/hadoop/spark/python/lib/pyspark.zip/pyspark/sql/utils.py", line 63, in deco
File "/opt/hadoop/spark/python/lib/py4j-0.10.7-src.zip/py4j/protocol.py", line 328, in get_return_value
py4j.protocol.Py4JJavaError: An error occurred while calling o36.load.
: java.util.ServiceConfigurationError: org.apache.spark.sql.sources.DataSourceRegister: Provider org.apache.spark.sql.kafka010.KafkaSourceProvider could not be instantiated
at java.util.ServiceLoader.fail(ServiceLoader.java:232)
at java.util.ServiceLoader.access$100(ServiceLoader.java:185)
at java.util.ServiceLoader$LazyIterator.nextService(ServiceLoader.java:384)
at java.util.ServiceLoader$LazyIterator.next(ServiceLoader.java:404)
at java.util.ServiceLoader$1.next(ServiceLoader.java:480)
at scala.collection.convert.Wrappers$JIteratorWrapper.next(Wrappers.scala:43)
at scala.collection.Iterator$class.foreach(Iterator.scala:891)
at scala.collection.AbstractIterator.foreach(Iterator.scala:1334)
at scala.collection.IterableLike$class.foreach(IterableLike.scala:72)
at scala.collection.AbstractIterable.foreach(Iterable.scala:54)
at scala.collection.TraversableLike$class.filterImpl(TraversableLike.scala:247)
at scala.collection.TraversableLike$class.filter(TraversableLike.scala:259)
at scala.collection.AbstractTraversable.filter(Traversable.scala:104)
at org.apache.spark.sql.execution.datasources.DataSource$.lookupDataSource(DataSource.scala:630)
at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:194)
at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:167)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:244)
at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
at py4j.Gateway.invoke(Gateway.java:282)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:238)
at java.lang.Thread.run(Thread.java:748)
Caused by: java.lang.NoSuchMethodError: org.apache.spark.internal.Logging.$init$(Lorg/apache/spark/internal/Logging;)V
at org.apache.spark.sql.kafka010.KafkaSourceProvider.<init>(KafkaSourceProvider.scala:44)
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
at java.lang.reflect.Constructor.newInstance(Constructor.java:423)
at java.lang.Class.newInstance(Class.java:442)
at java.util.ServiceLoader$LazyIterator.nextService(ServiceLoader.java:380)
... 24 more
执行spark-submit --version也可以得到以下版本：
(base) [hadoop@master ~]$ spark-submit --version
Welcome to
____ __
/ __/__ ___ _____/ /__
_\ \/ _ \/ _ `/ __/ '_/
/___/ .__/\_,_/_/ /_/\_\ version 2.4.4
/_/
Using Scala version 2.11.12, OpenJDK 64-Bit Server VM, 1.8.0_222
Branch
Compiled by user on 2019-08-27T21:21:38Z
Revision
Url
Type --help for more information.
答案 0 :(得分：1)
我最终通过降级到特定的Spark版本2.4.0解决了它。这是我使用的版本：
spark=2.4.0
kafka=2.12-2.3.0
scala=2.11.12
openJDK=1.8.0_222
这里是spark-submit：
spark-submit --packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.4.0,org.apache.kafka:kafka-clients:2.3.0 --master yarn --deploy-mode client /opt/hadoop/spark/spark-application/main/kafka-spark-structured-stream.py
答案 1 :(得分：0)
这可能是由于您的应用程序依赖性所致；我认为Kafka客户端与您使用的Spark版本之间存在不兼容...
我在使用Scala时遇到了同样的错误，我通过降级到Spark 2.3而不是2.4解决了它。