Question

我的Azure Monitor日志中的Clickstream数据采用以下格式：

       Timestamp             Category  Session_ID    Step_Name
10/22/2019, 9:28:14.868 AM      A        ++9Ti        step 1    
10/22/2019, 9:28:18.034 AM      A        ++9Ti        step 2    
10/22/2019, 9:28:22.487 AM      A        ++9Ti        step 3
10/23/2019, 7:02:02.527 AM      B        ++MoY        step 1    
10/23/2019, 7:02:09.244 AM      B        ++MoY        step 2    
10/23/2019, 7:02:21.156 AM      B        ++MoY        step 3        <-- 
10/23/2019, 7:02:27.195 AM      B        ++MoY        step 3        <--
10/23/2019, 7:15:13.544 AM      A        ++0a3        step 1    
10/23/2019, 7:15:35.438 AM      A        ++0a3        step 2

我需要获取消费者在“类别”中每个步骤上花费的平均时间

此外，当重复执行步骤时（例如session_ID ='++ MoY'中的步骤3），我们需要在计算平均值时采用最新的时间戳。

示例：类别A在步骤2上花费的平均时间为（3.166 + 21.894）/ 2 = 12.53秒。（注意：时间戳记给出了完成步骤的时间）

Answer 1

您可以尝试以下操作

a）使用arg_max()按步骤/类别获取最新信息

b）在prev()之后使用order by计算每个步骤的持续时间

datatable(Timestamp:datetime, Category:string, Session_ID:string, Step_Name:string)
[
    datetime(10/22/2019, 9:28:14.868 AM), 'A', '++9Ti', 'step 1',
    datetime(10/22/2019, 9:28:18.034 AM), 'A', '++9Ti', 'step 2',
    datetime(10/22/2019, 9:28:22.487 AM), 'A', '++9Ti', 'step 3',
    datetime(10/23/2019, 7:02:02.527 AM), 'B', '++MoY', 'step 1',
    datetime(10/23/2019, 7:02:09.244 AM), 'B', '++MoY', 'step 2',
    datetime(10/23/2019, 7:02:21.156 AM), 'B', '++MoY', 'step 3',
    datetime(10/23/2019, 7:02:27.195 AM), 'B', '++MoY', 'step 3',
    datetime(10/23/2019, 7:15:13.544 AM), 'A', '++0a3', 'step 1',
    datetime(10/23/2019, 7:15:35.438 AM), 'A', '++0a3', 'step 2',
]
| summarize arg_max(Timestamp, *) by Step_Name, Session_ID
| order by Session_ID asc, Timestamp asc
| extend duration = iff(Session_ID == prev(Session_ID), Timestamp - prev(Timestamp), 0s)
| summarize avg(duration) by Step_Name, Category
| where Step_Name == "step 2" and Category == "A"

Azure Monitor日志（Kusto查询语言）中一列内的日期时间差

1 个答案: