Question

我正在尝试制作一个简单的游戏

会发生什么事，就是玩家会被各种物体击中，从而导致生命值的增加/减少。

mainGame（）;创建只是为了查看其是否正常工作。

在编译时我得到了

(.text$_ZN5gamer7setDataEv[__ZN5gamer7setDataEv]+0x117)||undefined reference to `gamer::mainGame()'|

我尝试了friend关键字，但这给了我未定义引用对象的错误

class gamer
{
public:
    string gName;
    int gHealth;
    int continueGame;
    void mainGame();

    void setData()
    {

        cout << "Enter your name " <<endl;
        cin >> gName;

        srand(time(0));

        gHealth = 100 + (rand()%200);

        cout << gName << " has health of " << gHealth << endl;
        cout << "Would you like to continue ? 0 for yes" << endl;
        cin >> continueGame;

        if (continueGame == 0)
        {
            mainGame();
        }
    }
};

void mainGame()
    {
        gamer gamer;
        while(gamer.gHealth >= 0 || gamer.gHealth <= 500)
        {
            cout << " aaaaaa" << endl;
            gamer.gHealth -= 50;
            cout << gamer.gHealth << endl ;
        }
    }

Answer 1

您已声明了mainGame函数作为您的gamer类的成员，但从未真正定义。您接近了，但是忘记了在定义中声明它是该类的成员。以下应该可以工作：

void gamer::mainGame() // This is a member function of `gamer`, so declare it as such!
    {
    //  gamer gamer; // We don't need this reference, as the member function will have...
        while(gHealth >= 0 || gHealth <= 500) // ... an implied "this" object when called
        {
            cout << " aaaaaa" << endl;
            gHealth -= 50; // Just using the member name on its own is enough to get it.
            cout << gHealth << endl ;
        }
    }

在成员函数中，您不需要代码即可声明该类的对象！当调用该函数（由类的对象）时，该函数有效地接收到指向调用它的对象的指针。您可以使用this关键字明确地访问该指针，但是通常不需要。只需在该函数中使用成员变量的名称，即可为调用该函数的对象引用该成员变量。

无法从C ++中的类正确传输数据

1 个答案: