Question

我的数组如下

 createItem(): FormGroup {
    return this.formBuilder.group({
      staffMemberId: ['',],
      name: ['',],

    });
  }
   addItem(): void {
    this.projectFundingItems = this.formProjectGeneralData.get('staffMembers') as FormArray;
    this.projectFundingItems.push(this.createItem());
  }


  onTabChanged($event) {
    let clickedIndex = $event.index;
    let length = (<FormArray>this.formData.controls['staffMembers']).length;
    if (clickedIndex === length) {
      if ((<FormArray>this.formData.controls['staffMembers']).at(length - 1).dirty) {
        this.addItem();
        this.selectedTabIndex = clickedIndex - 1;
      } else {
        if (this.formData.staffMembers.length === clickedIndex) {
          this.addItem();
        }
        this.selectedTabIndex = clickedIndex - 1;
      }
    }
  }

我想针对特定的user_id过滤测试，例如，如果user_id = 4，我希望得到此结果

test_list = [
{ 
    id: 1,
    test_name: 'Test 1',
    members: [
        {
            user_id: 3
        },
        {
            user_id: 4
        }
    ],
},
{ 
    id: 2,
    test_name: 'Test 2',
    members: [
        {
           user_id: 4
        },
        {
            user_id: 5
        },
    ],
},
{ 
    id: 3,
    test_name: 'Test 2',
    members: [
        {
            user_id: 8
        },  
        {
            user_id: 10
        },
    ],
}
]

我已经尝试过了，但是只返回了成员

{ 
    id: 1,
    ...
},
{ 
    id: 2,
    ...
},

在这种情况下，有人可以帮我吗？

Answer 1

检查.some数组中的members个对象是否具有您要查找的user_id：

test_list = [{
    id: 1,
    test_name: 'Test 1',
    members: [{
        user_id: 3
      },
      {
        user_id: 4
      }
    ],
  },
  {
    id: 2,
    test_name: 'Test 2',
    members: [{
        user_id: 4
      },
      {
        user_id: 5
      },
    ],
  },
  {
    id: 3,
    test_name: 'Test 2',
    members: [{
      user_id: 8
    }]
  }
];

const filtered = test_list.filter(
  ({ members }) => members.some(
    ({ user_id }) => user_id === 4
  )
);
console.log(filtered);

Answer 2

您可以使用.reduce()和.filter()数组方法来获得所需的结果。

请检查以下工作代码段：

const arr = [{"id":1,"test_name":"Test 1","members":[{"user_id":3},{"user_id":4}]},{"id":2,"test_name":"Test 2","members":[{"user_id":4},{"user_id":5}]},{"id":3,"test_name":"Test 2","members":[{"user_id":8}]}];

const data = arr.reduce((r,{ members,...rest }) => {
  let rec = members.filter(o => o.user_id === 4)
  if(rec.length){
    rest.members = rec;
    r.push(rest);
  }
  return r;
},[]);

console.log(data);

Answer 3

希望这行得通。

  var members = item.members;
  var filterById =members.filter((item1)=>{
    return (item1.user_id===4)
  });
  return filterById.length > 0;
});
console.log(test_List_by_id)```

数组内的过滤器数组

3 个答案: