如何从字符串列表中删除空格

Question

我有一个字符串列表，如果每个项目都超过一个空格，则需要修剪所有空格。

original = ['1   0    1', 'how is it \n going?', 'hey how are you      today?', '0']
without_spaces = [item.replace('\s+', ' ', regex=True) for item in original]

我的预期输出是：

print(original)
['1 0 1', 'how is it going?', 'hey how are you today?', '0']

对此有何想法？

Answer 1

您可以将re.sub()用于此目的：

import re
original = ['1   0    1', 'how is it \n going?', 'hey how are you      today?', '0']
without_spaces = [re.sub('\s+', ' ', item) for item in original]
print(without_spaces)

输出将是：

['1 0 1', 'how is it going?', 'hey how are you today?', '0']

Answer 2

' '.join(mystring.split())

这将按单词拆分，并使用" "将它们重新连接为单个字符串。

另一种方法是：

import re

re.sub('\s+', ' ', mystring).strip()

希望这会有所帮助。祝你好运。

Answer 3

类似的事情应该起作用

import re
original = ['1   0    1', 'how is it \n going?', 'hey how are you      today?', '0']
without_spaces = [re.sub("\s+", " ", item) for item in original]

print(without_spaces)