C#二进制文件发布请求

时间:2019-10-22 16:20:48

标签: c# http http-headers

我正在处理一个第三方API,该API坚持将二进制文件上传请求格式化为而没有设置Content-Type头值为multipart/form-data,并且具有以下头:

Content-Type: application/octet-stream
Content-Disposition: filename*=UTF-8''file.zip

HttpRequestMessageHttpContent.Headers.ContentDisposition.DispositionType不允许我实现此目的,因为我无法根据需要设置值,或者它们会自动设置它们。

我接受此API可能未遵循HTTP标准,但它不是我的,因此对它没有影响。

我的尝试无效

    using (HttpClient client = new HttpClient())
    {
        client.DefaultRequestHeaders.ExpectContinue = false;
        FileStream fs = new FileStream(@"e:\dev\TestHalfB.docx", FileMode.Open);

        HttpRequestMessage req = new HttpRequestMessage(HttpMethod.Post, <Uri>);
        HttpContent fc = new StreamContent(fs);
        var mpContent = new MultipartFormDataContent();
        mpContent.Add(fc);
        fc.Headers.ContentType = MediaTypeHeaderValue.Parse("application/octet-stream");
        req.Content = fc;
        fc.Headers.ContentDisposition.DispositionType = "filename*=UTF-8''TestHalfB.docx";

        using (var response = await client.SendAsync(req))
        {
            response.EnsureSuccessStatusCode();
            var resp = await response.Content.ReadAsStringAsync();
        }

        fs.Close();
    }

有人知道我可以使用较低级别的API或有任何建议吗?

关键是如何将Content-Disposition标头设置为所需的值。

3 个答案:

答案 0 :(得分:0)

可以请您尝试一下。

   HttpContent fileStreamContent = new StreamContent(paramFileStream);

    using (var formData = new MultipartFormDataContent())
    {
        formData.Add(fileStreamContent, "file1", "file1");
        var response = client.PostAsync(actionUrl, formData).Result;
    }

答案 1 :(得分:0)

我不得不改用WebRequest

    WebRequest request = WebRequest.Create("https://cloud.memsource.com/web/api2/v1/projects/{id}/jobs?token={token}");
    request.Method = "POST";
    byte[] byteArray = File.ReadAllBytes(@"E:\Dev\TestHalfB.docx");
    request.ContentType = "application/octet-stream";
    request.ContentLength = byteArray.Length;
    request.Headers.Add("Content-Disposition", "filename*=UTF-8''TestHalfB.docx");
    Stream dataStream = request.GetRequestStream();
    dataStream.Write(byteArray, 0, byteArray.Length);
    dataStream.Close();
    WebResponse response = request.GetResponse();
    ((HttpWebResponse)response).StatusDescription.Dump();

答案 2 :(得分:-1)

这应该对您有用(或者至少让您入门,因为它未经测试):

HttpRequestMessage req = new HttpRequestMessage(HttpMethod.Post, <Uri>);
using (FileStream fs = new FileStream(@"e:\dev\TestHalfB.docx", FileMode.Open))
{
    byte[] fb = new byte[(int)fs.Length]; // assumes your file size will fit into an int
    await fs.ReadAsync(fb, 0, (int)fs.Length);
    req.Content = new ByteArrayContent(fb);
    req.Content.Headers.ContentType = MediaTypeHeaderValue.Parse("application/octet-stream");
    req.Content.Headers.ContentDisposition.FileNameStar = "UTF-8''TestHalfB.docx";

    using (var response = await client.SendAsync(req))
    {
        response.EnsureSuccessStatusCode();
        var resp = await response.Content.ReadAsStringAsync();
    }
}